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In a set of numbers from 100 to 1000 inclusive, how many integers are

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Director
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In a set of numbers from 100 to 1000 inclusive, how many integers are  [#permalink]

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New post Updated on: 19 May 2015, 04:28
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In a set of numbers from 100 to 1000 inclusive, how many integers are odd and do not contain the digit "5"?

A. 180
B. 196
C. 286
D. 288
E. 324

M03-12

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Originally posted by alimad on 13 May 2008, 17:56.
Last edited by Bunuel on 19 May 2015, 04:28, edited 1 time in total.
Renamed the topic, edited the question, added the OA and moved to PS forum.
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Re: In a set of numbers from 100 to 1000 inclusive, how many integers are  [#permalink]

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New post 24 Jan 2009, 15:07
8
2
x-ALI-x wrote:
Can someone tell my why we multiply 4*8*9, whats the logic behind multiplying versus another approach?

Thanks,
Ali


we need to find odd numbers without digit 5 from 100 to 1000 (i.e same as odd numbers without digit 5 from 100 to 999)

let say number= XYZ
Z= units digit
Y= tenths digit
X= Hundredth's digit

For any 3 digit number to be odd, Unit digit must be odd
So Z can be filled with 1,3,7,9 (we are exlcuding digit 5) = 4 ways.
Y can be filled with 0,1,2,3,4,6,7,8,9 (we are ecluding digit 5) = 9 ways
X can be filled with 1,2,3,4,6,7,8,9 (we are exlcuding digits 0 and 5 .. ) = 8 ways

No of ways= 4*9*8= 288
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Re: In a set of numbers from 100 to 1000 inclusive, how many integers are  [#permalink]

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New post 13 May 2008, 18:54
alimad wrote:
In a set of numbers from 100 to 1000 inclusive, how many integers are odd and do not contain the digit "5"?



180
196
286
288
324


lets see..in all there are 450 odd numbers!

of which 105, 115, 125, 135..10 such number per 100 numbrs 10+10(from 15X) 20-1=19 such numbers cause i already counted 155 twice..
19*8=152 such numbers..plus 100 from 5XX..so total to be excluded 152+100-450=198..

I would guess the number is 196..
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Re: In a set of numbers from 100 to 1000 inclusive, how many integers are  [#permalink]

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New post 13 May 2008, 19:11
3
2
Should be 288.
We have to find the total number of 3-digit odd numbers not having 5 as a digit.
Units digits will be among 1,3,7,9
Tenth digits will be among 0,1,2,3,4,6,7,8,9
Hundredth digits will be among 1,2,3,4,6,7,8,9
So total numbers = 4*9*8 =288
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Re: In a set of numbers from 100 to 1000 inclusive, how many integers are  [#permalink]

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New post 24 Jan 2009, 13:36
Can someone tell my why we multiply 4*8*9, whats the logic behind multiplying versus another approach?

Thanks,
Ali
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Re: In a set of numbers from 100 to 1000 inclusive, how many integers are  [#permalink]

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New post 18 May 2015, 15:43
x2suresh wrote:
x-ALI-x wrote:
Can someone tell my why we multiply 4*8*9, whats the logic behind multiplying versus another approach?

Thanks,
Ali


we need to find odd numbers without digit 5 from 100 to 1000 (i.e same as odd numbers without digit 5 from 100 to 999)

let say number= XYZ
Z= units digit
Y= tenths digit
X= Hundredth's digit

For any 3 digit number to be odd, Unit digit must be odd
So Z can be filled with 1,3,7,9 (we are exlcuding digit 5) = 4 ways.
Y can be filled with 0,1,2,3,4,6,7,8,9 (we are ecluding digit 5) = 9 ways
X can be filled with 1,2,3,4,6,7,8,9 (we are exlcuding digits 0 and 5 .. ) = 8 ways

No of ways= 4*9*8= 288


Dear x2suresh,
Clearly your approach sets the benchmark!
Please share more of such examples. Thanks.
My approach was cumbersome and time consuming:
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Re: In a set of numbers from 100 to 1000 inclusive, how many integers are  [#permalink]

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New post 19 May 2015, 04:29
1
1
alimad wrote:
In a set of numbers from 100 to 1000 inclusive, how many integers are odd and do not contain the digit "5"?

A. 180
B. 196
C. 286
D. 288
E. 324

M03-12


Examine what digits these set members can contain:

First digit (hundreds): 8 choices (1, 2, 3, 4, 6, 7, 8, 9 - cannot be 0 or 5)
Second digit (tens): 9 choices (0, 1, 2, 3, 4, 6, 7, 8, 9 - cannot be 5)
Last digit (units): 4 choices (1, 3, 7, 9 - cannot be 0, 2, 4, 5, 6, 8)

The answer is 8∗9∗4=32∗9=288.

Answer: D.
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Re: In a set of numbers from 100 to 1000 inclusive, how many integers are  [#permalink]

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New post 26 Sep 2018, 07:22
consider all three digit number between 100-1000
XYZ

Z can take only 4 values : 1,3,7 and 9 (It cannot take 5)
y can take 9 values : 0,1,2,3,4,6,7,8,9 (It cannot take 5)
X can take 8 values : 1,2,3,4,6,7,8,9 (IT cannot take 0 and 5)
Hence the answer : 4*9*8= 288
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Re: In a set of numbers from 100 to 1000 inclusive, how many integers are &nbs [#permalink] 26 Sep 2018, 07:22
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In a set of numbers from 100 to 1000 inclusive, how many integers are

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