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In a triangle ABC where ∠B is a right angle:

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In a triangle ABC where ∠B is a right angle:  [#permalink]

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New post 03 Jan 2019, 15:29
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In a triangle ABC where ∠B is a right angle: side AB has a length of x units, side AC has a length of 12 units, and side BC has a length of x + 8 units. What is the area of ABC in square units?

A. 10
B. 15
C. 16.5
D. 20
E. 22

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Re: In a triangle ABC where ∠B is a right angle:  [#permalink]

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New post 03 Jan 2019, 19:50
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Mahmoudfawzy83 wrote:
In a triangle ABC where ∠B is a right angle: side AB has a length of x units, side AC has a length of 12 units, and side BC has a length of x + 8 units. What is the area of ABC in square units?

A. 10
B. 15
C. 16.5
D. 20
E. 22



So angle B is 90, so the side opposite to it, AC is hypotenuse..
With sides x, x+8 and 12...
\(x^2+(x+8)^2=12^2......x^2+x^2+16x+64=144.......x^2+8x=40.....x (x+8)=40\)

The area of this triangle is \(\frac{1}{2}*x(x+8)=\frac{40}{2}=20\)

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Re: In a triangle ABC where ∠B is a right angle:   [#permalink] 03 Jan 2019, 19:50
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In a triangle ABC where ∠B is a right angle:

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