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Manager  B
Joined: 08 Sep 2015
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In an increasing sequence of 5 consecutive even integers, the sum of  [#permalink]

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Question Stats: 90% (01:28) correct 10% (01:38) wrong based on 117 sessions

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In an increasing sequence of 5 consecutive even integers, the sum of the second, third, and fourth integer
is 132. What is the sum of the first and last integers?

A.84
B.86
C.88
D.90
E.92
Math Expert V
Joined: 02 Sep 2009
Posts: 62398
Re: In an increasing sequence of 5 consecutive even integers, the sum of  [#permalink]

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BPHASDEU wrote:
In an increasing sequence of 5 consecutive even integers, the sum of the second, third, and fourth integer
is 132. What is the sum of the first and last integers?

A.84
B.86
C.88
D.90
E.92

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Re: In an increasing sequence of 5 consecutive even integers, the sum of  [#permalink]

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1
1
2
let the number be a-2, a-1, a, a+1, a+2
according to the question, a -1 +a +a +1 = 132
or 3a = 132
or a = 44
therefore first integer +last integer = a-2 +a+2 = 2a = 2*44 = 88

Option C
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Re: In an increasing sequence of 5 consecutive even integers, the sum of  [#permalink]

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1
Let the 5 consecutive even numbers be x, x+2, x+4, x+6, x+8

Given: x+2+x+4+x+6 = 132
=> 3x+12 = 132
=> x = 40

Since x = 40; x+8 = 48

x + (x+8) = 40+48 = 88 (C)
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Re: In an increasing sequence of 5 consecutive even integers, the sum of  [#permalink]

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1
2
Hi All,

This question can be solved with the Average Formula...

We're told that the sequence is 5 CONSECUTIVE EVEN integers and the sum of the 2nd, 3rd and 4th is 132. Since the numbers are CONSECUTIVE, the "middle" one will be the AVERAGE of the 2nd, 3rd and 4th.

Average = Sum/Number of terms = 132/3 = 44

Thus, since the 2nd, 3rd and 4th terms are 42, 44 and 46 respectively. By extension, the sum of the 1st and 5th terms is: 40 + 48 = 88

GMAT assassins aren't born, they're made,
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Joined: 07 Dec 2014
Posts: 1240
In an increasing sequence of 5 consecutive even integers, the sum of  [#permalink]

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BPHASDEU wrote:
In an increasing sequence of 5 consecutive even integers, the sum of the second, third, and fourth integer
is 132. What is the sum of the first and last integers?

A.84
B.86
C.88
D.90
E.92

132/3=44=median
44-4=40
44+4=48
40+48=88
C
Intern  Joined: 22 Dec 2013
Posts: 6
Location: United States
Schools: Wharton '20
Re: In an increasing sequence of 5 consecutive even integers, the sum of  [#permalink]

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BPHASDEU wrote:
In an increasing sequence of 5 consecutive even integers, the sum of the second, third, and fourth integer
is 132. What is the sum of the first and last integers?

A.84
B.86
C.88
D.90
E.92

let the numbers be a-2d,a-d,a,a+d,a+2d

sum of 2nd,3rd and 4th will be a-d+a+a+d=3a = 132 --> a=44

since the numbers are consecutive even integers d should be 2, so the numbers are 40,42,44,46,48

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Status: QA & VA Forum Moderator
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Location: India
GPA: 3.5
Re: In an increasing sequence of 5 consecutive even integers, the sum of  [#permalink]

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BPHASDEU wrote:
In an increasing sequence of 5 consecutive even integers, the sum of the second, third, and fourth integer is 132. What is the sum of the first and last integers?

A.84
B.86
C.88
D.90
E.92

Let the numbers be " a , a +1 , a + 2 , a + 3 & a +4 "

Now, $$( a + 1 ) + ( a + 2 ) + ( a + 3 ) = 132$$

Or, $$3a + 6 = 132$$

Or, $$3a = 126$$

Or, $$a = 42$$

So, Sum of the first and last Integer must be 42 + 46 = 90, the answer must be (D)
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Target Test Prep Representative G
Affiliations: Target Test Prep
Joined: 04 Mar 2011
Posts: 2801
Re: In an increasing sequence of 5 consecutive even integers, the sum of  [#permalink]

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BPHASDEU wrote:
In an increasing sequence of 5 consecutive even integers, the sum of the second, third, and fourth integer
is 132. What is the sum of the first and last integers?

A.84
B.86
C.88
D.90
E.92

Letting x denote the smallest of these even consecutive integers, we can create the equation:

x + 2 + x + 4 + x + 6 = 132

3x + 12 = 132

3x = 120

x = 40

So the sum of the first and last integers is 40 + (40 + 8) = 40 + 48 = 88.

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Re: In an increasing sequence of 5 consecutive even integers, the sum of  [#permalink]

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_________________ Re: In an increasing sequence of 5 consecutive even integers, the sum of   [#permalink] 11 Mar 2020, 13:11
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