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# In an investigation, it was found that 20% of the employees who are vu

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Director
Joined: 25 Dec 2018
Posts: 558
Location: India
Concentration: General Management, Finance
GMAT Date: 02-18-2019
GPA: 3.4
WE: Engineering (Consulting)
In an investigation, it was found that 20% of the employees who are vu  [#permalink]

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06 Mar 2019, 01:15
1
6
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95% (hard)

Question Stats:

16% (03:36) correct 84% (03:22) wrong based on 95 sessions

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In an investigation, it was found that 20% of the employees who are vulnerable to Mycobacterial infection are less than 17 years of age and 30% of the employees who are not vulnerable to Mycobacterial infection are more than or equal to 17 years of age. If 16% of total employees are more than or equal to 17 years of age and are vulnerable to Mycobacterial infection, then what percentage of the employees, that are 17 years old or more, are not vulnerable to Mycobacterial infection?

A) 16.6%
B) 24%
C) 30%
D) 60%
E) 80%
Intern
Joined: 20 Jan 2019
Posts: 9
Re: In an investigation, it was found that 20% of the employees who are vu  [#permalink]

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06 Mar 2019, 05:07
2
Hi there,

I am constantly getting 24%, anyone here that got 60% ?

And where is that question from ?
Intern
Joined: 30 Jan 2019
Posts: 6
Re: In an investigation, it was found that 20% of the employees who are vu  [#permalink]

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07 Mar 2019, 15:51
1
1
20% of the employees who are vulnerable to Mycobacterial infection are less than 17 years of age
30% of the employees who are not vulnerable to Mycobacterial infection are more than or equal to 17 years of age.

If 16% of total employees are more than or equal to 17 years of age and are vulnerable to Mycobacterial infection, then what percentage of the employees, that are 17 years old or more, are not vulnerable to Mycobacterial infection?

16% = (% vulnerable to infection)*(% of total employees more than or equal to 17 years of age)
% vulnerable to infection above refers to those 17 or above = 80%
16% = 80%*(% of total employees more than or equal to 17) ==> 0.16 = 0.80*x
% total employees >=17 is 20% (x = 0.2)

% employees >=17 not vulnerable = 0.2*0.3 = 0.6 ==> 60%
Intern
Joined: 01 Mar 2019
Posts: 3
Re: In an investigation, it was found that 20% of the employees who are vu  [#permalink]

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11 Mar 2019, 09:30
ashszn wrote:
Hi there,

I am constantly getting 24%, anyone here that got 60% ?

And where is that question from ?

I am also getting 24%.

16% of employees are both vulnerable and 17+

which means that 20% of the total employees are vulnerable. (0.16 = 0.8 * V, V = 20%)

Now 30% of Non Vulnerable Group is 17 + (0.3*NV = 0.3*(1 - V) = 0.3*(0.8) = 0.24)

24% of employees are non vulnerable and 17 +
Intern
Joined: 20 Jan 2019
Posts: 9
In an investigation, it was found that 20% of the employees who are vu  [#permalink]

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12 Mar 2019, 03:43
1
Hi there,

we didn't get the question right. The question asked for the percentage of >17 that are not vulnerable so you would take 24/40 -> 60%.

Hope that helps.

lgiacomazzi wrote:
ashszn wrote:
Hi there,

I am constantly getting 24%, anyone here that got 60% ?

And where is that question from ?

I am also getting 24%.

16% of employees are both vulnerable and 17+

which means that 20% of the total employees are vulnerable. (0.16 = 0.8 * V, V = 20%)

Now 30% of Non Vulnerable Group is 17 + (0.3*NV = 0.3*(1 - V) = 0.3*(0.8) = 0.24)

24% of employees are non vulnerable and 17 +
Intern
Joined: 20 Jan 2018
Posts: 7
Location: India
GPA: 4
WE: Supply Chain Management (Transportation)
Re: In an investigation, it was found that 20% of the employees who are vu  [#permalink]

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12 Mar 2019, 21:44
yashu612 wrote:
20% of the employees who are vulnerable to Mycobacterial infection are less than 17 years of age
30% of the employees who are not vulnerable to Mycobacterial infection are more than or equal to 17 years of age.

If 16% of total employees are more than or equal to 17 years of age and are vulnerable to Mycobacterial infection, then what percentage of the employees, that are 17 years old or more, are not vulnerable to Mycobacterial infection?

16% = (% vulnerable to infection)*(% of total employees more than or equal to 17 years of age)
% vulnerable to infection above refers to those 17 or above = 80%
16% = 80%*(% of total employees more than or equal to 17) ==> 0.16 = 0.80*x
% total employees >=17 is 20% (x = 0.2)

% employees >=17 not vulnerable = 0.2*0.3 = 0.6 ==> 60%

Hey Yashu........Kindly check this statement
% employees >=17 not vulnerable = 0.2*0.3 = 0.6 ==> 60%[/quote]

in my opinion 0.2*0.3 equals 0.06
Intern
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Location: Brazil
Concentration: Strategy, General Management
GPA: 2.96
In an investigation, it was found that 20% of the employees who are vu  [#permalink]

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14 Mar 2019, 13:36
1
mangamma wrote:
In an investigation, it was found that 20% of the employees who are vulnerable to Mycobacterial infection are less than 17 years of age and 30% of the employees who are not vulnerable to Mycobacterial infection are more than or equal to 17 years of age. If 16% of total employees are more than or equal to 17 years of age and are vulnerable to Mycobacterial infection, then what percentage of the employees, that are 17 years old or more, are not vulnerable to Mycobacterial infection?

A) 16.6%
B) 24%
C) 30%
D) 60%
E) 80%

- 20% of employees who are vulnerable are younger than 17: (v|17-) = 20% * v
- 30% of employees who are not vulnerable are older than 17: (n|17+) = 30% * n

From this, we can write the complementary equations:
- 80% of employees who are vulnerable are older than 17: (v|17+) = 80% * v
- 70% of employees who are not vulnerable are younger than 17: (n|17-) = 70% * n

Now, the last piece of information:
- 16% of all employees are older than 17 and vulnerable: (v|17+) = 16% * T

This means that (v|17+) = 80% * v = 16% * T
v = 20% * T (20% of all employees are vulnerable)

This also means that 80% of all employees are not vulnerable (n = 80% * T)

Finally, the question asks for the percentage of employees who are 17 years or older that are not vulnerable. In other words, $$\frac{(n|17+)}{(17+)}$$
The total number of employees 17 years or older is equal to (v|17+) + (n|17+).

We already know that (v|17+) = 16% * T
(n|17+) = 30% * n = 30% * 80% * T = 24% * T

Adding the two together, we can conclude that 40% of all employees are 17 years or older. $$\frac{(n|17+)}{(17+)}$$ = 24%*T / 40%*T = 60%

Manager
Joined: 07 May 2018
Posts: 60
Re: In an investigation, it was found that 20% of the employees who are vu  [#permalink]

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15 Mar 2019, 23:33
FTGreco wrote:
mangamma wrote:
In an investigation, it was found that 20% of the employees who are vulnerable to Mycobacterial infection are less than 17 years of age and 30% of the employees who are not vulnerable to Mycobacterial infection are more than or equal to 17 years of age. If 16% of total employees are more than or equal to 17 years of age and are vulnerable to Mycobacterial infection, then what percentage of the employees, that are 17 years old or more, are not vulnerable to Mycobacterial infection?

A) 16.6%
B) 24%
C) 30%
D) 60%
E) 80%

- 20% of employees who are vulnerable are younger than 17: (v|17-) = 20% * v
- 30% of employees who are not vulnerable are older than 17: (n|17+) = 30% * n

From this, we can write the complementary equations:
- 80% of employees who are vulnerable are older than 17: (v|17+) = 80% * v
- 70% of employees who are not vulnerable are younger than 17: (n|17-) = 70% * n

Now, the last piece of information:
- 16% of all employees are older than 17 and vulnerable: (v|17+) = 16% * T

This means that (v|17+) = 80% * v = 16% * T
v = 20% * T (20% of all employees are vulnerable)

This also means that 80% of all employees are not vulnerable (n = 80% * T)

Finally, the question asks for the percentage of employees who are 17 years or older that are not vulnerable. In other words, $$\frac{(n|17+)}{(17+)}$$
The total number of employees 17 years or older is equal to (v|17+) + (n|17+).

We already know that (v|17+) = 16% * T
(n|17+) = 30% * n = 30% * 80% * T = 24% * T

Adding the two together, we can conclude that 40% of all employees are 17 years or older. $$\frac{(n|17+)}{(17+)}$$ = 24%*T / 40%*T = 60%

Hi,

Could you please explain how you got 17+)[/fraction][/m] as 40%.

Regards,

Ritvik
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Concentration: Strategy, General Management
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Re: In an investigation, it was found that 20% of the employees who are vu  [#permalink]

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16 Mar 2019, 20:30
menonrit wrote:
Hi,

Could you please explain how you got 17+)[/fraction][/m] as 40%.

Regards,

Ritvik

In order to find how many of the total amount of employees in the company are 17 years or older (17+), we have to add all subgroups that includes people in this category - in this case, the subgroup of vulnerable people older than 17 (v|17+) and the subgroup of not vulnerable people older than 17 (n|17+).

This simply means that (17+) = (v|17+) + (n|17+) = 16% + 24% = 40%.

If you don't understand any other part of this solution, feel free to ask!
Intern
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Location: United States
GMAT 1: 720 Q56 V40
Re: In an investigation, it was found that 20% of the employees who are vu  [#permalink]

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10 Jan 2020, 09:18
3
Two way relative frequency tables

Two-way relative frequency tables show what percent of data points fit in each category. We can use row relative frequencies or column relative frequencies, it just depends on the context of the problem.
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File comment: MBA HOUSE KEY CONCEPT: Two way table technique

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Re: In an investigation, it was found that 20% of the employees who are vu   [#permalink] 10 Jan 2020, 09:18
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