sondenso wrote:

daszero wrote:

And going for the trifecta..

What we know

employees >= 5 = 40% -- 1

employees <10 = 90 %

This implies that 10% of the employees have >= 10yrs experience. -- 2

We are also given that 16 employees have greater than 10 yrs experience.

If n is the total number of employees. 0.1n=16 or n = 160

out of these 30% are in the range, [ 5 < yrs of experience < 10 ]

(remember that >5 includes the employees who have greater than 10yrs of work ex)

Thus answer is 0.3n = 48 (A).

Man it took 3 minutes longer to type the answer than it took to solve the problem.

I used the table to solve it, but I lost in the gem. Could you figure out the boldface and colored above? I still not get it. Thank you!

Let me rephrase the answer, lets see if this conveys it better

.

The problem says that 40% of the employees have work experience of at least 5 years

The problem also says that 16 employees have work experience of at least 10 years.

If the total number of employees = n,

the number of people who are between 5 and 10 years of experience = \(((40/100) * n) - 16\) -- 1

The problem also says that 90% of employees have < 10 years experience. From this statement we see that the 16 employees who have more than 10 years of experience, constitute only

10% of the work force.

Thus \((10/100) * n =16\)

Solving for this we get n=160. Substitute this in 1 and the answer works out to 48..