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Re: In how many ways can 3 people out of 14 people be given 3 [#permalink]

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07 Nov 2012, 07:20

Actually, I arrived at The answer a different way. I used The permutation formula 13!\11! To get 156, and then multiples by 3 for the 3 different ways jack could place.

Re: In how many ways can 3 people out of 14 people be given 3 [#permalink]

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27 Dec 2012, 22:02

My approach:

Since I know that Jack is awarded and another 2 so I have: J _ _

How many ways to select 2 from the remaining 13? 13!/2!1! = 78 Thus, this means there are 78 possible selection of winners from the 14. All of which includes Jack and some other 2 persons.

How many ways to award a group? We can imagine ranking three people as first, second and third. Thus we can get the possible arrangements of 3 people. 3! = 6

Re: In how many ways can 3 people out of 14 people be given 3 [#permalink]

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10 Apr 2016, 08:43

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Re: In how many ways can 3 people out of 14 people be given 3 [#permalink]

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07 Aug 2016, 21:39

Hey! I tried an alternate approach where the no. Of ways of choosing prize winners is 1*13*12 and no of permutations is 3! So my answer is 3!*1*13*12 Where am I going wrong here though

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