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# In May, Josep sold 40% of the computers that were sold by

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In May, Josep sold 40% of the computers that were sold by [#permalink]

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19 Feb 2008, 01:31
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In May, Josep sold 40% of the computers that were sold by the store at which he works. In June, Josep sold 60% of the computers sold by the store. Did Josep sell more than twice as many computers in June as he did in May?
(1) The number of computers that the other employees sold was higher in June than in May.
(2) Josep sold more than half of the computers that were sold by the store during the months of May and June.

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Senior Manager
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19 Feb 2008, 11:11
A alone is sufficient.

St2 is just re-iterating the statement in the question.

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19 Feb 2008, 11:24
suntaurian wrote:
A alone is sufficient.

St2 is just re-iterating the statement in the question.

Can you explain how A is sufficient?
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19 Feb 2008, 11:42
rca215 wrote:
suntaurian wrote:
A alone is sufficient.

St2 is just re-iterating the statement in the question.

Can you explain how A is sufficient?

In May, Josep sold 40% of the computers that were sold by the store at which he works. In June, Josep sold 60% of the computers sold by the store. Did Josep sell more than twice as many computers in June as he did in May?
St 1: The number of computers that the other employees sold was higher in June than in May.

Josef sold 40 % of the total computers sold in May. He sold 60% of the total sold in June.
In May other employees sold 60% computers and in Jun they sold 40% of the total.

St 1 : 40% of the total sold by other employees in June is more than 60% of the total sold by the other employees in May.
This means that the total # of computers sold in Jun was more than the total sold in May, coz the 40% of the # in Jun > 60% of the # in May. Hence the # in Jun > # in May.

Now lets look back at Josep. Even if the # of computers sold in Jun and May was same, Josep would have sold 1.5 times the computers he sold in May. Also we know that the total # of computers sold in Jun is greater than in May, which means the # of computers Josep sold in Jun is more than 1.5 times the # he sold in May.

Hope it helps...

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19 Feb 2008, 11:57
A
--
J: Total # sold in June, M: Total # sold in May

1) For others (0.4J > 0.6M); J/M>1.5
For Joesph, (In may: 0.4M, In June: 0.6J=0.6*1.5M=0.9M); 0.4M < 2(0.4M) + 0.1M
He did sell twice as many in June,
SUFF

2) 0.4M + 0.6J > (M+J)/2 => 0.4M + 0.6J > 0.5M + 0.5J; implies J>M
INSUFF

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Director
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19 Feb 2008, 16:58
Just plug in numbers

10 second question

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Director
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19 Feb 2008, 18:06
I don't prefer plugging in numbers in such cases.
I would go for algebraic solution.
Let's say x - the total comps sold in may
y-the total comps sold in June

Joseph sold 0.4 x in may and 0.6y is June.
As per stmt1: 0.4y > 0.6x ===> y> 1.5x
this means 0.6y > 0.9x, which is greater than 0.8x
hence suff.

Stmt2: just gives y>x , Insuff

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Re: DS: Josep (percents)   [#permalink] 19 Feb 2008, 18:06
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