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Re: In Papersville, 6,000 people read either the Herald or the Tribune. Ho [#permalink]
chetan2u wrote:
SajjadAhmad wrote:
In Papersville, 6,000 people read either the Herald or the Tribune. How many people read both newspapers?

(1) Of the people in Papersville, 2,000 read the Herald only.

(2) Of the people in Papersville, 2,500 read the Tribune only.


The sentence '6000 people read either the Herald or the Tribune. ' tells us that there are three groups.. only herald, only tribune, and both.
Combined.. statements give us only herald and only tribune ..
So the third group can be found by subtracting the two groups.. both =6000-2000-2500=1500.

C



What about the group that does not read either newspaper?
In the formula, Total = A + B - Both + None
How did you know the last term is 0?
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Re: In Papersville, 6,000 people read either the Herald or the Tribune. Ho [#permalink]
SajjadAhmad wrote:
In Papersville, 6,000 people read either the Herald or the Tribune. How many people read both newspapers?

(1) Of the people in Papersville, 2,000 read the Herald only.

(2) Of the people in Papersville, 2,500 read the Tribune only.


The question stem tells us there is nobody who reads none. So None=0. Both=?

Statement 1: H only = 2000

Statement 2: T only = 2500

Combined : Total = 6000-0-2000-2500=1500 Both.

Answer C.
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Re: In Papersville, 6,000 people read either the Herald or the Tribune. Ho [#permalink]
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SajjadAhmad wrote:
In Papersville, 6,000 people read either the Herald or the Tribune. How many people read both newspapers?

(1) Of the people in Papersville, 2,000 read the Herald only.

(2) Of the people in Papersville, 2,500 read the Tribune only.


Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Visit https://www.mathrevolution.com/gmat/lesson for details.

The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. We should simplify conditions if necessary.

Assume h, t and b are the numbers of people who read Herald, Tribune and both, respectively.
Then we have h + t + b = 6,000.

Since we have 3 variables (h, t and b) and 1 equation, C is most likely the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2)

We have h = 2,000 from condition 1) and t = 2500 from condition 2).
Thus we have b = 6,000 - h - b = 6,000 - 2,000 - 2,500 = 1,500.

Since both conditions together yield a unique solution, they are sufficient.

Therefore, C is the answer.

Normally, in problems which require 2 equations, such as those in which the original conditions include 2 variables, or 3 variables and 1 equation, or 4 variables and 2 equations, each of conditions 1) and 2) provide an additional equation. In these problems, the two key possibilities are that C is the answer (with probability 70%), and E is the answer (with probability 25%). Thus, there is only a 5% chance that A, B, or D is the answer. This occurs in common mistake types 3 and 4. Since C (both conditions together are sufficient) is the most likely answer, we save time by first checking whether conditions 1) and 2) are sufficient, when taken together. Obviously, there may be cases in which the answer is A, B, D, or E, but if conditions 1) and 2) are NOT sufficient when taken together, the answer must be E.
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Re: In Papersville, 6,000 people read either the Herald or the Tribune. Ho [#permalink]
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