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In ΔPQS above, if PQ =3 and PS = 4, then

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In ΔPQS above, if PQ =3 and PS = 4, then [#permalink]

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New post 14 Aug 2009, 07:55
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In ΔPQS above, if PQ =3 and PS = 4, then
(A) 9/4
(B) 12/5
(C) 16/5
(D) 15/4
(E)20/3
[Reveal] Spoiler:
B

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Re: triangle [#permalink]

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New post 14 Aug 2009, 08:00
[quote="vannu"]In ΔPQS above, if PQ =3 and PS = 4, then
(A)9/4
(B) 12/5
(C) 16/5
(D) 15/4
(E)20/3


i guess the question is asking about PR

this a pythagron triblet 3,4,5 , thus the hyp = 5
well

area of the triangle = 1/2 *3*4 = 6 ( using perpen sides)

area ( hyp and pr) = 6 , hyp = 5 thus pr = 12/5
pr = 6*2/5 = 12/5

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Re: triangle [#permalink]

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New post 15 Jan 2012, 03:37
there are two ways to calculate area of PQS. area remains same, so both are equal.
3*4/2 = PR*5/2

PR = 12/5

*btw, this is known has "bh" principle i.e. PQ*PS = PR*QS.
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Kudos [?]: 1227 [0], given: 48

Re: triangle   [#permalink] 15 Jan 2012, 03:37
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In ΔPQS above, if PQ =3 and PS = 4, then

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