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In rectangle ABCD shown above, sides AB and CD pass through the center [#permalink]
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Bunuel wrote:

In rectangle ABCD shown above, sides AB and CD pass through the centers of the two circles. If AB = 12 and AD = 16, what is the area of the shaded region?

(A) 120
(B) 156
(C) 192
(D) 192 – 36π
(E) 192 – 72π

Attachment:
2017-11-17_0947.png

Area of rectangle = (12*16) = 192

Area of two semi-circles = Area of one circle
Radius = \(\frac{1}{2}(12)=6\)
Area = \(πr^2 = 36π\)

(Rectangle area) - (one circle area) = shaded area

\(192 - 36π\)

Answer D
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Re: In rectangle ABCD shown above, sides AB and CD pass through the center [#permalink]
The Area of the Rectangle is 12 x 16 = 192. The two circular halves. So it is 192-36Phi
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Re: In rectangle ABCD shown above, sides AB and CD pass through the center [#permalink]
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