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# In right triangle triangle ABC, C is a right angle; DE is parallel to

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Re: In right triangle triangle ABC, C is a right angle; DE is parallel to [#permalink]
Use 45-45-90 triangle concept. Area of triangle ABC would be 1 unit square and area of 2 small triangles would be 2*(1/8). Therefore, fraction of area of shaded area to triangle ABC would be 1/4

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Re: In right triangle triangle ABC, C is a right angle; DE is parallel to [#permalink]
Hi Bunuel
Do you have any plan to post the solution?
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Re: In right triangle triangle ABC, C is a right angle; DE is parallel to [#permalink]
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In right triangle triangle ABC, C is a right angle; DE is parallel to [#permalink]
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Sol. Draw a line on AB from C. let’s assume it as h.
Area of the triangle ABC =1/2×AB×h
Since shaded triangles are similar to the triangle ABC, hence shaded triangles are also right angle triangle. Height of the shaded triangle is ½ of the height ‘h’.
Combined base of both shaded triangles = PQ = DE = ½ of AB (as per midpoint theorem of triangle. )
Base of one shaded triangle = ¼ of AB
Area of both of the Shaded triangles =2×1/2×1/4 AB×1/2h=1/8×AB×h
Fraction of area shaded =((1/8×AB×h ))/((1/2×AB×h) )=1/4