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In square PQRS above, if ST = TQ and SU = RU, then the area of the sha

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In square PQRS above, if ST = TQ and SU = RU, then the area of the sha  [#permalink]

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New post 16 Oct 2018, 01:25
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Question Stats:

94% (00:47) correct 6% (00:37) wrong based on 20 sessions

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Re: In square PQRS above, if ST = TQ and SU = RU, then the area of the sha  [#permalink]

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New post 16 Oct 2018, 01:30
Since SQ is the diagonal of the square PQRS. Area of triangle SRQ will be half of PQRS. Now Triangle TUR is 1/4 of the area of SRQ. Hence the triangle TUR will be 1/8 of the area of the triangle PQRS.

B is the answer.
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Re: In square PQRS above, if ST = TQ and SU = RU, then the area of the sha  [#permalink]

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New post 16 Oct 2018, 01:40
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ST=TQ tells us that T is the center of the square.
SU=RU tells us that U is the midpoint of SR.

This translates to TUR being \(\frac{1}{2}\) of TSR
TSR is \(\frac{1}{2}\) of SQR

SQR is half your square.

There can be 8 equal segments of area TUR in the square, therefore TUR is \(\frac{1}{8}\) the area of the square.
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Re: In square PQRS above, if ST = TQ and SU = RU, then the area of the sha   [#permalink] 16 Oct 2018, 01:40
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In square PQRS above, if ST = TQ and SU = RU, then the area of the sha

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