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Bunuel
In store A there are 10 pairs of pants for every 40 store B has. The price ratio between the pants in store B and the pants in store A is 3:4. If all the pants were sold in both places until the stock ran out, what is the ratio between the total amount stores A earned to the total amount store B earned?

A. 3:16.
B. 2:3.
C. 1:3.
D. 3:4.
E. 2:5.

1st statement : ratio of pants

Store A : Store B

10x : 40x

X:4X

Price :

4y:3y

Total revenue

4xy : 12xy

1:3

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Bunuel
In store A there are 10 pairs of pants for every 40 store B has. The price ratio between the pants in store B and the pants in store A is 3:4. If all the pants were sold in both places until the stock ran out, what is the ratio between the total amount stores A earned to the total amount store B earned?

A. 3:16.
B. 2:3.
C. 1:3.
D. 3:4.
E. 2:5.

Number of pants in B = 4 * number of pants in A
or A/B= 1/4

Price Ratio between A and B = 4:3

Total amount earned= Number of pants *price

1/4 *4/3= 1/3

C is the answer
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Bunuel
In store A there are 10 pairs of pants for every 40 store B has. The price ratio between the pants in store B and the pants in store A is 3:4. If all the pants were sold in both places until the stock ran out, what is the ratio between the total amount stores A earned to the total amount store B earned?

A. 3:16.
B. 2:3.
C. 1:3.
D. 3:4.
E. 2:5.
This problem's wrinkles are that the ratios switch, and the wording of the first sentence might be confusing.

Quantity ratio (for every 40 pairs that B has, A has 10 pairs):

\(\frac{A}{B}\) = \(\frac{10x}{40x}\) = \(\frac{1x}{4x}\)

A has 1x or 1
B has 4x or 4*

Price ratio ("price ratio between pants in B and pants A is 3:4") - I keep the same variables as those on the top and bottom of the first ratio

\(\frac{A}{B}\) = \(\frac{4y}{3y}\)

A charges 4y or 4
B charges 3y or 3

All pants are sold. What is ratio between the total amount (quantity * price) that A earned to total amount B earned?

A earned 1 * 4 = 4

B earned 4 * 3 = 12

Ratio of A's total earnings to B's total earnings:

\(\frac{4}{12}\) = \(\frac{1}{3}\) = 1:3

Answer C

*(x and y are ratio multipliers; as long as the ratio stays the same when solving at the end, you can assume values such as 1 and 4, and 4 and 3)
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