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Math Expert V
Joined: 02 Sep 2009
Posts: 58103
In the addition shown below A, B, C, and D are distinct digits. How ma  [#permalink]

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Difficulty:   85% (hard)

Question Stats: 38% (02:20) correct 62% (02:13) wrong based on 53 sessions

### HideShow timer Statistics In the addition shown below A, B, C, and D are distinct digits. How many different values are possible for D ?

(A) 2
(B) 4
(C) 7
(D) 8
(E) 9

Attachment: f247ec6fe2d36c608337f8763645addb01b26338.png [ 1.85 KiB | Viewed 471 times ]

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GMAT Club Legend  D
Joined: 18 Aug 2017
Posts: 4790
Location: India
Concentration: Sustainability, Marketing
Schools: INSEAD, HEC '22, IIM
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Re: In the addition shown below A, B, C, and D are distinct digits. How ma  [#permalink]

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Bunuel wrote: In the addition shown below A, B, C, and D are distinct digits. How many different values are possible for D ?

(A) 2
(B) 4
(C) 7
(D) 8
(E) 9

Attachment:

total digits = 10
if a,b,c occupy 1 digit position each and all are distinct then value of D integer can be 10-3 ; 7
IMO C
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Director  V
Joined: 27 May 2012
Posts: 853
In the addition shown below A, B, C, and D are distinct digits. How ma  [#permalink]

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Bunuel wrote: In the addition shown below A, B, C, and D are distinct digits. How many different values are possible for D ?

(A) 2
(B) 4
(C) 7
(D) 8
(E) 9

Attachment:

Key points :
1) All are distinct
2) All are single digit integers.

In any addition we always start from the right hand side.
Let us assume D =1 then A+B= 1 or 0 +1=1 or 1+0=1 so if A =1 then B=0 or Vice versa
let us take A=1 and B=0 and proceed, in the second column if D=1 then C has to be 0 this contradicts point 1 above , as all integers are supposed to be distinct. C and B both cannot be 0, hence D cannot be 1

Let us assume D=2 then A=0 and B=2 or vice versa , we can't have both as 1, as all are supposed to be distinct.
Put D=2 in second column then C=0, this again violates point 1 , hence D cannot be 2

Let us assume D=3 then first column A+B=1+2 or 2+1 let us take first case A=1 and B=2 , second column put d=3 then C=0 ,Third Column B + A= D so 2+1=3, Fourth Column B+C= B so 2+0=2, Fifth Column A+B=D so 1+2=3
So D can be 3 .

There is a pattern here in all those cases in which C=0 and is distinct ,we have a valid value for D.
So possible values of D are = 3,4,5,6,7,8 and 9, hence 7 values .
Ans C.

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- Stne In the addition shown below A, B, C, and D are distinct digits. How ma   [#permalink] 26 Apr 2019, 05:05
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# In the addition shown below A, B, C, and D are distinct digits. How ma

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