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Math Expert V
Joined: 02 Sep 2009
Posts: 56357
In the biology lab of "Jefferson" High School there are 0.037*10^5 ger  [#permalink]

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Difficulty:   15% (low)

Question Stats: 86% (01:36) correct 14% (02:02) wrong based on 96 sessions

### HideShow timer Statistics In the biology lab of "Jefferson" High School there are 0.037*10^5 germs, equally divided among 74000*10^(-3) Petri dishes. How many germs live happily in a single dish?

A. 10
B. 20
C. 30
D. 40
E. 50

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Re: In the biology lab of "Jefferson" High School there are 0.037*10^5 ger  [#permalink]

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Bunuel wrote:
In the biology lab of "Jefferson" High School there are 0.037*10^5 germs, equally divided among 74000*10^(-3) Petri dishes. How many germs live happily in a single dish?

A. 10
B. 20
C. 30
D. 40
E. 50

E

0.037*10^5 can be written as 3700
74000*10^(-3) can be written as 74
Required= 3700/74= 50
Intern  Joined: 24 Jun 2015
Posts: 12
Re: In the biology lab of "Jefferson" High School there are 0.037*10^5 ger  [#permalink]

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Bunuel wrote:
In the biology lab of "Jefferson" High School there are 0.037*10^5 germs, equally divided among 74000*10^(-3) Petri dishes. How many germs live happily in a single dish?

A. 10
B. 20
C. 30
D. 40
E. 50

IMO Solution = [(0.037*10^5)] / [74000*10^(-3)] = [(37*10^2)] / [(37*2000*10^(-3)] = 100 / [2000*10^(-3)] = 1 /[20*10^(-3)] = 1 /[20*(1/10^3)]
= 1 / [20*(1/1000)] = 1 / (20/1000) = 1 / (1/50) = 50 / 1 = 50. IMO 'E'.
CEO  V
Joined: 12 Sep 2015
Posts: 3857
Re: In the biology lab of "Jefferson" High School there are 0.037*10^5 ger  [#permalink]

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Top Contributor
Bunuel wrote:
In the biology lab of "Jefferson" High School there are 0.037*10^5 germs, equally divided among 74000*10^(-3) Petri dishes. How many germs live happily in a single dish?

A. 10
B. 20
C. 30
D. 40
E. 50

Germs per dish = (total number of germs)/(total number of dishes)

total number of germs = 0.037 x 10^5
= 3700 [moved the decimal point 5 spaces to the LEFT to get 3700]

total number of dishes = 74000 x 10^(-3)
= 74 [moved the decimal point 3 spaces to the RIGHT to get 3700]

So, Germs per dish = (3700)/(74)
= (37)(100)/(37)(2)
= 100/2
= 50

Cheers,
Brent
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Re: In the biology lab of "Jefferson" High School there are 0.037*10^5 ger  [#permalink]

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Bunuel wrote:
In the biology lab of "Jefferson" High School there are 0.037*10^5 germs, equally divided among 74000*10^(-3) Petri dishes. How many germs live happily in a single dish?

A. 10
B. 20
C. 30
D. 40
E. 50

$$0.037*10^5 = 3700$$
$$74000*10^(-3) = 74$$

So, $$\frac{3700}{74} = 50$$ germs live happily , Answer must be (E)
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Re: In the biology lab of "Jefferson" High School there are 0.037*10^5 ger  [#permalink]

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Bunuel wrote:
In the biology lab of "Jefferson" High School there are 0.037*10^5 germs, equally divided among 74000*10^(-3) Petri dishes. How many germs live happily in a single dish?

A. 10
B. 20
C. 30
D. 40
E. 50

The number of germs that live happily in a single dish is:

0.037*10^5/74,000*10^(-3)

(0.037 x 100,000)/(74,000 x 1/1000)

3700/74 = 50

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If you find one of my posts helpful, please take a moment to click on the "Kudos" button. Re: In the biology lab of "Jefferson" High School there are 0.037*10^5 ger   [#permalink] 23 Aug 2018, 17:03
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