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In the diagram above, ∠J = ∠M, ∠K = ∠N,

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In the diagram above, ∠J = ∠M, ∠K = ∠N, [#permalink]

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New post 08 Mar 2013, 14:35
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two similar triangles.JPG
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In the diagram above, ∠J = ∠M, ∠K = ∠N, and side lengths are as shown. Given this, y must equal
(A) r/sx
(B) x/sr
(C) sr/x
(D) sx/r
(E) rx/s


For a review of everything you need to know about similar geometric figures for the GMAT, as well as a complete solution to this question, see this blog:
http://magoosh.com/gmat/2013/gmat-math-similar-shapes/
[Reveal] Spoiler: OA

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Re: In the diagram above, ∠J = ∠M, ∠K = ∠N, [#permalink]

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New post 09 Mar 2013, 14:36
Similar Triangle
Y/x = s/r
Hence Y = sx/r
Choice D
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Re: In the diagram above, ∠J = ∠M, ∠K = ∠N, [#permalink]

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New post 27 Oct 2013, 21:09
I understood that the triangles were similar but wasn't sure how that was going to help me get the answer.

I plugged some numbers and derived the answer for y in my hypothetical situation

I said \(r= 5 ,s = 10, x= 10\). I figured the ratio of the lengths of the two sides would hold since they are similar triangle.

So my equation looked like this.
\(\frac{r}{s}\)= \(\frac{5}{10}\) and \(\frac{x}{y}=\frac{10}{y}\)

With this simple equation y=20. So i backed solved to get to the equation.

\(\frac{r}{s}\)=\(\frac{1}{2}\)and \(y=2*x\) or \(20=2*10\). Therefore to get 20 I had to take the reciprocal of \(\frac{r}{s}\) and multiply that by x.

So my answer would be\(\frac{sx}{r}\) or choice D.

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Re: In the diagram above, ∠J = ∠M, ∠K = ∠N, [#permalink]

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New post 27 Mar 2015, 11:16
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Re: In the diagram above, ∠J = ∠M, ∠K = ∠N,   [#permalink] 27 Mar 2015, 11:16
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