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In the diagram above, ∠J = ∠M, ∠K = ∠N,

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Magoosh GMAT Instructor
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In the diagram above, ∠J = ∠M, ∠K = ∠N, [#permalink]

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08 Mar 2013, 14:35
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two similar triangles.JPG [ 20.78 KiB | Viewed 2202 times ]

In the diagram above, ∠J = ∠M, ∠K = ∠N, and side lengths are as shown. Given this, y must equal
(A) r/sx
(B) x/sr
(C) sr/x
(D) sx/r
(E) rx/s

For a review of everything you need to know about similar geometric figures for the GMAT, as well as a complete solution to this question, see this blog:
http://magoosh.com/gmat/2013/gmat-math-similar-shapes/
[Reveal] Spoiler: OA

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Re: In the diagram above, ∠J = ∠M, ∠K = ∠N, [#permalink]

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09 Mar 2013, 14:36
Similar Triangle
Y/x = s/r
Hence Y = sx/r
Choice D
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Re: In the diagram above, ∠J = ∠M, ∠K = ∠N, [#permalink]

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27 Oct 2013, 21:09
I understood that the triangles were similar but wasn't sure how that was going to help me get the answer.

I plugged some numbers and derived the answer for y in my hypothetical situation

I said $$r= 5 ,s = 10, x= 10$$. I figured the ratio of the lengths of the two sides would hold since they are similar triangle.

So my equation looked like this.
$$\frac{r}{s}$$= $$\frac{5}{10}$$ and $$\frac{x}{y}=\frac{10}{y}$$

With this simple equation y=20. So i backed solved to get to the equation.

$$\frac{r}{s}$$=$$\frac{1}{2}$$and $$y=2*x$$ or $$20=2*10$$. Therefore to get 20 I had to take the reciprocal of $$\frac{r}{s}$$ and multiply that by x.

So my answer would be$$\frac{sx}{r}$$ or choice D.

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Re: In the diagram above, ∠J = ∠M, ∠K = ∠N, [#permalink]

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27 Mar 2015, 11:16
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Re: In the diagram above, ∠J = ∠M, ∠K = ∠N,   [#permalink] 27 Mar 2015, 11:16
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