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In the diagram above, O is the center of the circle

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In the diagram above, O is the center of the circle [#permalink]

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In the diagram above, O is the center of the circle, DC = a and DO = b. What is the area of the circle?

Statement #1: \(a^2 - 2ab + b^2 = 36\)

Statement #2: a + b = 22


For a discussion of the important algebra formulas involved, as well as a full solution to this particular problem, see:
http://magoosh.com/gmat/2013/three-alge ... -the-gmat/
[Reveal] Spoiler: OA

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Kudos [?]: 7720 [1] , given: 95

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Re: In the diagram above, O is the center of the circle [#permalink]

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New post 01 May 2013, 11:13
Option A.

DC= a and DO =b
OC= DC-DO = b-a = radius of the circle.

From stmt 1:
(b-a)^2=36 or (b-a)=6 and area = 36pi. sufficient

From stmt 2:

we know a+b but we need to know the value of b-a. hence this is insufficient.

Kudos [?]: 14 [0], given: 16

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Re: In the diagram above, O is the center of the circle [#permalink]

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New post 19 May 2016, 01:00
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Re: In the diagram above, O is the center of the circle [#permalink]

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New post 15 Apr 2017, 17:29
mdbharadwaj wrote:
Option A.

DC= a and DO =b
OC= DC-DO = b-a = radius of the circle.

From stmt 1:
(b-a)^2=36 or (b-a)=6 and area = 36pi. sufficient

From stmt 2:

we know a+b but we need to know the value of b-a. hence this is insufficient.


I believe it's (a-b) we're looking for here.

(a-b)(a-b)=r^2=36 So, area is 36pi

Kudos [?]: 22 [0], given: 122

Re: In the diagram above, O is the center of the circle   [#permalink] 15 Apr 2017, 17:29
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In the diagram above, O is the center of the circle

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