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In the diagram above, O is the center of the circle [#permalink]
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01 May 2013, 10:40
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In the diagram above, O is the center of the circle, DC = a and DO = b. What is the area of the circle?
Statement #1: \(a^2  2ab + b^2 = 36\)
Statement #2: a + b = 22For a discussion of the important algebra formulas involved, as well as a full solution to this particular problem, see: http://magoosh.com/gmat/2013/threealge ... thegmat/
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Re: In the diagram above, O is the center of the circle [#permalink]
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01 May 2013, 11:13
Option A.
DC= a and DO =b OC= DCDO = ba = radius of the circle.
From stmt 1: (ba)^2=36 or (ba)=6 and area = 36pi. sufficient
From stmt 2:
we know a+b but we need to know the value of ba. hence this is insufficient.

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Re: In the diagram above, O is the center of the circle [#permalink]
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19 May 2016, 01:00
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Re: In the diagram above, O is the center of the circle [#permalink]
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15 Apr 2017, 17:29
mdbharadwaj wrote: Option A.
DC= a and DO =b OC= DCDO = ba = radius of the circle.
From stmt 1: (ba)^2=36 or (ba)=6 and area = 36pi. sufficient
From stmt 2:
we know a+b but we need to know the value of ba. hence this is insufficient. I believe it's (ab) we're looking for here. (ab)(ab)=r^2=36 So, area is 36pi

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Re: In the diagram above, O is the center of the circle
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15 Apr 2017, 17:29







