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# In the diagram above, O is the center of the circle

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Magoosh GMAT Instructor
Joined: 28 Dec 2011
Posts: 4667
In the diagram above, O is the center of the circle [#permalink]

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01 May 2013, 10:40
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2
00:00

Difficulty:

25% (medium)

Question Stats:

77% (01:01) correct 23% (01:19) wrong based on 166 sessions

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circle with segments.png [ 14.94 KiB | Viewed 2014 times ]

In the diagram above, O is the center of the circle, DC = a and DO = b. What is the area of the circle?

Statement #1: $$a^2 - 2ab + b^2 = 36$$

Statement #2: a + b = 22

For a discussion of the important algebra formulas involved, as well as a full solution to this particular problem, see:
http://magoosh.com/gmat/2013/three-alge ... -the-gmat/

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Magoosh Test Prep

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Manager
Joined: 26 Feb 2013
Posts: 52
Concentration: Strategy, General Management
GMAT 1: 660 Q50 V30
WE: Consulting (Telecommunications)
Re: In the diagram above, O is the center of the circle [#permalink]

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01 May 2013, 11:13
Option A.

DC= a and DO =b
OC= DC-DO = b-a = radius of the circle.

From stmt 1:
(b-a)^2=36 or (b-a)=6 and area = 36pi. sufficient

From stmt 2:

we know a+b but we need to know the value of b-a. hence this is insufficient.
Manager
Joined: 13 Dec 2013
Posts: 161
Location: United States (NY)
GMAT 1: 710 Q46 V41
GMAT 2: 720 Q48 V40
GPA: 4
WE: Consulting (Consulting)
Re: In the diagram above, O is the center of the circle [#permalink]

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15 Apr 2017, 17:29
Option A.

DC= a and DO =b
OC= DC-DO = b-a = radius of the circle.

From stmt 1:
(b-a)^2=36 or (b-a)=6 and area = 36pi. sufficient

From stmt 2:

we know a+b but we need to know the value of b-a. hence this is insufficient.

I believe it's (a-b) we're looking for here.

(a-b)(a-b)=r^2=36 So, area is 36pi
Re: In the diagram above, O is the center of the circle   [#permalink] 15 Apr 2017, 17:29
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