sudeeptasahu29 wrote:
Attachment:
Capture.PNG
In the diagram to the right, triangle PQR has a right angle at Q and line segment QS is perpendicular to PR. If line segment PS has a length of 16 and line segment SR has a length of 9, what is the area of triangle PQR?
A. 72
B. 96
C. 108
D. 150
E. 200
Standard type of right triangles are with sides 3 4 5 , 5 12 13, 8 15 17, and 7 24 25.
1) In this question we have hypotenuse as 25 (a multiple of 5) so we can choose 3 4 5 and 5 12 13.
2) Now hypotenuse is the largest side of a right triangle , this leaves only 3 4 5.
In this case multiply each side of 3 4 5 with 5 (since hypotenuse is a multiple of 5) we get 15 20 25.
Now calculate the area! (15*20)/2=150
hit kudos if you like or tell me where I am wrong
so that's how I did it too - i wonder if this is in some way incorrect? Because it's so simple, 16 + 9 = 25 that's a perfect square, so can assume a right angle 3-4-5 but bigger, multiply 5*5, makes it 15-20-25 triangle, 15*20*1/2 is the area?