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# In the figure above, CE = 5, BD = 8, and the area of quadrilateral ABC

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Math Expert
Joined: 02 Sep 2009
Posts: 56268
In the figure above, CE = 5, BD = 8, and the area of quadrilateral ABC  [#permalink]

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23 Nov 2015, 12:56
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5% (low)

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89% (01:01) correct 11% (01:32) wrong based on 51 sessions

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In the figure above, CE = 5, BD = 8, and the area of quadrilateral ABCD is 36. What is the area of △ABD ?

(A) 4
(B) 9
(C) 16
(D) 20
(E) 56

Attachment:

geo.gif [ 2.63 KiB | Viewed 3023 times ]

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Re: In the figure above, CE = 5, BD = 8, and the area of quadrilateral ABC  [#permalink]

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23 Nov 2015, 19:28
Area of quadrilateral ABCD = Area of triangle BCD + Area of triangle ABD = 36
Area of triangle BCD = 1/2 * CE * BD = 1/2 * 5 * 8 = 20

Area of triangle ABD = 36-20 = 16

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In the figure above, CE = 5, BD = 8, and the area of quadrilateral ABC  [#permalink]

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23 Nov 2015, 19:30
Bunuel wrote:

In the figure above, CE = 5, BD = 8, and the area of quadrilateral ABCD is 36. What is the area of △ABD ?

(A) 4
(B) 9
(C) 16
(D) 20
(E) 56

Attachment:
geo.gif

Area of △BCD = $$\frac{1}{2}$$*BD*CE = $$\frac{1}{2}$$*8*5 = 20
Area of △ABD = Area of quadrilateral ABCD - Area of △BCD = 36 - 20 = 16

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Re: In the figure above, CE = 5, BD = 8, and the area of quadrilateral ABC  [#permalink]

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23 Aug 2018, 20:54
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Re: In the figure above, CE = 5, BD = 8, and the area of quadrilateral ABC   [#permalink] 23 Aug 2018, 20:54
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