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In the figure above, equilateral triangle ABC is inscribed

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Joined: 20 Jan 2014
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Re: In the figure above, equilateral triangle ABC is inscribed [#permalink]

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New post 21 Dec 2014, 22:24
Thanks Karishma and Bunnuel ,

I was doing it wrong :( - This shows difference between theoretical knowledge and practical application.
Lesson learnt hard way :)
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Re: In the figure above, equilateral triangle ABC is inscribed [#permalink]

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New post 15 Apr 2016, 10:41
ulm wrote:
Attachment:
Circle.JPG
In the figure above, equilateral triangle ABC is inscribed in the circle. If the length of arc ABC is 24, what is the approximate diameter of the circle?

A. 5
B. 8
C. 11
D. 15
E. 19


Since the triangle is an equilateral triangle , we can say

AB = BC = AC ( Property of Equilateral Triangle )

Further the arc lengths AB = BC = AC

We are given AB + BC = 24

Or, 2AB (AB + AB ) = 24

Or, AB = 12

As AB = AC , we can say AC = 12

Thus the total circumference of the circle is 12 + 12 + 12 = 36

Now, 2πr = 36

So, πr = 18

Or, 22/7 r = 18

or, r = 5.72

So, Diameter will be 2r = 2*5.72 => ~ 12

Since this is a question of approximation we choose option (C) 11 :-D :lol:
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Re: In the figure above, equilateral triangle ABC is inscribed [#permalink]

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New post 08 Jun 2017, 16:41
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Attached is a visual that should help.
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Screen Shot 2017-06-08 at 4.31.56 PM.png
Screen Shot 2017-06-08 at 4.31.56 PM.png [ 225.94 KiB | Viewed 264 times ]


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Re: In the figure above, equilateral triangle ABC is inscribed   [#permalink] 08 Jun 2017, 16:41

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