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# In the figure above, equilateral triangle ABC is inscribed

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Current Student
Joined: 20 Jan 2014
Posts: 175

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Location: India
Concentration: Technology, Marketing
Re: In the figure above, equilateral triangle ABC is inscribed [#permalink]

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21 Dec 2014, 22:24
Thanks Karishma and Bunnuel ,

I was doing it wrong - This shows difference between theoretical knowledge and practical application.
Lesson learnt hard way
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Kudos [?]: 72 [0], given: 120

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Re: In the figure above, equilateral triangle ABC is inscribed [#permalink]

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15 Apr 2016, 10:41
ulm wrote:
Attachment:
Circle.JPG
In the figure above, equilateral triangle ABC is inscribed in the circle. If the length of arc ABC is 24, what is the approximate diameter of the circle?

A. 5
B. 8
C. 11
D. 15
E. 19

Since the triangle is an equilateral triangle , we can say

AB = BC = AC ( Property of Equilateral Triangle )

Further the arc lengths AB = BC = AC

We are given AB + BC = 24

Or, 2AB (AB + AB ) = 24

Or, AB = 12

As AB = AC , we can say AC = 12

Thus the total circumference of the circle is 12 + 12 + 12 = 36

Now, 2πr = 36

So, πr = 18

Or, 22/7 r = 18

or, r = 5.72

So, Diameter will be 2r = 2*5.72 => ~ 12

Since this is a question of approximation we choose option (C) 11
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Abhishek....

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Kudos [?]: 1116 [0], given: 327

Senior Manager
Status: Professional GMAT Tutor
Affiliations: AB, cum laude, Harvard University (Class of '02)
Joined: 10 Jul 2015
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Kudos [?]: 504 [1], given: 56

Location: United States (CA)
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Re: In the figure above, equilateral triangle ABC is inscribed [#permalink]

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08 Jun 2017, 16:41
1
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Top Contributor
Attached is a visual that should help.
Attachments

Screen Shot 2017-06-08 at 4.31.56 PM.png [ 225.94 KiB | Viewed 264 times ]

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Kudos [?]: 504 [1], given: 56

Re: In the figure above, equilateral triangle ABC is inscribed   [#permalink] 08 Jun 2017, 16:41

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