In the figure above, point O is the center of the circle and OC = AC =

Thank you.

I must have overlooked something because I get:

x+x+(180-2y)+y= 180
2x-y=0
2x-2x= 0

Ignore the highlighted step.
after 2x - y = 0, when you take y to the other side, you get
2x = y

Without doing this step, how did you substitute 2x for y in the highlighted step?

How are we getting different variables x and y when the sides are equal. Can you explain Krishna. Cause three sides are equal shouldn't their angles be noted with the same variable?

I must have overlooked something because I get:

x+x+(180-2y)+y= 180
2x-y=0
2x-2x= 0[/quote]

Ignore the highlighted step.
after 2x - y = 0, when you take y to the other side, you get
2x = y

Without doing this step, how did you substitute 2x for y in the highlighted step?[/quote]
I see what I did. Below was my thought process:

x+x+(180-2y)+y= 180
2x-y=0 I then looked at the graph and applied the sum of two interior angles is equal to the opposite exterior which you labeled y. Once I got 2x= y I then went back to x+x+(180-2y)+y= 180 and thought I would end up with 5x= 180 but instead kept getting 2x-2x= 0

Something it's not quite right here.

I'm also stuck with the last calculation.

STEP 1
180-2x + y = 180
2x = y OK I KNOW HOW TO FIND THIS

STEP 2
Then I convert Y to become 2X
<AOB = x
<ABO = 2x
<BAO = x + (180-4x)-----Why I add x to 180-4x because that's how I think we get a straight line of 180 degree

therefore:
x + 2x + x + (180-4x) = 180
then I get 180 = 180

PLEASE HELP ME. TOTALLY STUCK

good explanation but I am not understand (the red angle=blue angle )?

[quote="VeritasPrepKarishma"]
Hi,

if OC = AC = AB, then how come the three angles are not equal? (it's illustrated as x, y, and y in your diagram versus all y's)

Thanks

When two sides of a triangle are equal, the angles opposite them are equal. OC and AC form triangle OAC. The angles opposite to these two will be equal angle AOC = OAC. But we can't say what the measure of the equal angles is.

While AC and BC form triangle ABC. Angles opposite these will be equal angle BAC = CBA. But we can't say what the measure of the equal angles is.

Note that just because the triangles share a side AC, it doesn't mean the opposite angles will all be of the same measure. They are angles in different triangles. The length of the side does not give the angle.

VeritasPrepKarishma hello

cant understand the logic behind this (180 - 2x) + y = 180 (straight angle) so 2x = y

if you are deducting 2x from 180 then why are you adding y ? there are 2x and 2y right and how 2x = y

why triangle OAB an isosceles and not an equilateral

please explain:)

have a great wekkend

In triangle OAC, OC = AC
That is why angle COA = angle OAC = x
So angle OCA = 180 - x - x = 180 - 2x

Also AC = BC, so in triangle ACB,
angle ACB = angle CBA = y

Angles OCA and ACB form a straight angle so
180 - 2x + y = 180

In triangle OAB, OA = OB = radius of the circle. But these are not equal to AB (so not equilateral)
Note that AB is actually equal to OC (and AC). OC is less than the radius of the circle.

If you would like a video explanation

https://gmatquantum.com/official-guides ... nt-review/

From GMAT Quantum

@brentprepnow cant we arrive at Angle ACB= 2x using external angle equals sum of opp interior angles?

We can definitely use that property to find angle ACB.
That said, many/most students aren't aware of the external angle property. So I don't use it in my solutions.

Cheers,
Brent

OFFICIAL GMAT EXPLANATION

Consider the figure above, where DB is a diameter of the circle with center O and AD is a chord. Since OC = AC, ΔOCA is isosceles and so the base angles, ∠AOC and ∠OAC, have the same degree measure. The measure of ∠AOC is given as x°, so the measure of ∠OAC is x°. Since AC = AB, ΔCAB is isosceles and so the base angles, ∠ACB and ∠ABC, have the same degree measure. The measure of each is marked as y°. Likewise, since OD and OA are radii of the circle, OD = OA, and ΔDOA is isosceles with base angles, ∠ADO and ∠DAO, each measuring z°. Each of the following statements is true:

i. The measure of ∠CAB is 180 − 2y since the sum of the measures of the angles of ΔCAB is 180.
ii. ∠DAB is a right angle (because DB is a diameter of the circle) and so z + x + (180 − 2y) = 90, or, equivalently, 2y − x − z = 90.
iii. z + 90 + y = 180 since the sum of the measures of the angles of right triangle ΔDAB is 180, or, equivalently, z = 90 − y.
iv. x = 2z because the measure of exterior angle ∠AOC to ΔAOD is the sum of the measures of the two opposite interior angles, ∠ODA and ∠OAD.
v. y = 2x because the measure of exterior angle ∠ACB to ΔOCA is the sum of the measures of the two opposite interior angles, ∠COA and ∠CAO.

Multiplying the final equation in (iii) by 2 gives 2z = 180 − 2y. But, x = 2z in (iv), so x = 180 − 2y. Finally, the sum of the measures of the angles of ΔCAB is 180 and so y + y + x = 180. Then from (v), 2x + 2x + x = 180, 5x = 180, and x = 36.

Another approach:

Since, AC = AB, Angle ACB = ABC;
Also, since OC = AC, Angle AOC = Angle OAC = x

Angle ACB is the external Angle to Triangle AOC at C. Therefore, Ange ACB = 2(Angle AOC) = 2*x =2x
Since Angle ACB = Angle ABC, Angle ABC = 2x

Now extend the radius OB to M, making it the diameter (Illustrated in the attached image)

In Triangle MAB, Angle MAB = 90 (Angle in a semi circle)
Also, Angle AMB = x/2 (Angle subtended at the arc is half the angle subtended at the centre)
Also, for Triangle MAB,
Angle MAB + Angle AMB + Angle MBA = 180 (Interior angles of a triangle)
i.e. 90 + x/2 + 2x = 180
or, 5x/2 = 90
or, x = 36

Therefore, (B) is the correct answer
This is an indirect method. In Hindi this approach would be called "Olte haath se seedha kaan pakadna" (Holding right ear with left hand). But if it hits you at the right time, it works

KarishmaB

I found it to be more intuitive to have angle CAB = 180-4x as the user indicated above. However, I tried solving for x using the angles for the whole larger triangle combined so angles
COA + OAB + CBA
In other words, I did x + 180-4x + 2x + x and then set it equal to 180 because that is all that the whole triangle can equal. However, everything canceled out. Why doesn't this work? Thank you for your help

OC=AC
Hence,Angle AOC=x=Angle OAC
Angle ACB=Angle AOC + Angle OAC(As per the rule)=2x
AC=AB(Given)
Hence,Angle ACB=Angle ABC=2x
OA=OB(radius of the same circle)
Hence,AOB is an isosceles triangle.
Angle OAB=Angle OBA(2x)
Angle OAB =Angle OAC(x)+Angle CAB(180-4x)
Hence,
2x=x+180-4x
5x=180
x=36

Option B