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# In the figure above, point O is the center of the circle, points A and

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Math Expert
Joined: 02 Sep 2009
Posts: 53066
In the figure above, point O is the center of the circle, points A and  [#permalink]

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11 Oct 2018, 02:02
00:00

Difficulty:

35% (medium)

Question Stats:

69% (01:28) correct 31% (01:29) wrong based on 31 sessions

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In the figure above, point O is the center of the circle, points A and C are located on the circle, and line segment BC is tangent to the circle. If the area of triangle OBC is 24, what is the length of AB?

(A) 2
(B) 4
(C) 6
(D) 8
(E) 10

Attachment:

Capture (4).JPG [ 21.32 KiB | Viewed 429 times ]

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Re: In the figure above, point O is the center of the circle, points A and  [#permalink]

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11 Oct 2018, 04:25
Area of triangle OBC= 24

$$\frac{1}{2}$$*BC*OC= 24

OC= $$\frac{48}{8}$$= 6

By Pythagoras triplet 8:6:10

Length of OB= 10

AB= OB - OA= 10-6= 4 (OA=OC, Radii of the Same Circle)

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Re: In the figure above, point O is the center of the circle, points A and   [#permalink] 11 Oct 2018, 04:25
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