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# In the figure above, square region ABCE and triangular region ACD each

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Math Expert
Joined: 02 Sep 2009
Posts: 47037
In the figure above, square region ABCE and triangular region ACD each [#permalink]

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28 Sep 2017, 23:53
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Difficulty:

25% (medium)

Question Stats:

90% (01:45) correct 10% (00:45) wrong based on 20 sessions

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In the figure above, square region ABCE and triangular region ACD each has area 36. What is the perimeter of triangle ACD?

(A) 24
(B) 12 + 12√2
(C) 36
(D) 18 + 18√2
(E) 36√2

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2017-09-29_1043_003.png [ 4.68 KiB | Viewed 533 times ]

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In the figure above, square region ABCE and triangular region ACD each [#permalink]

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29 Sep 2017, 01:51
Here ABCE area = 36
side(EC) = 6
AC = 6sqrt2

area of ACD = 36
perimeter
6 sqrt 2+6 sqrt 2+12
12+12sqrt2

Since AD = 12 , side ED= AD-ED =6, then angle ACD should be 90, SO AC = CD

In the figure above, square region ABCE and triangular region ACD each   [#permalink] 29 Sep 2017, 01:51
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