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In the figure above, the point on segment PQ that is twice as far from

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Math Expert
Joined: 02 Sep 2009
Posts: 64163
In the figure above, the point on segment PQ that is twice as far from  [#permalink]

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13 Dec 2017, 19:55
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Difficulty:

25% (medium)

Question Stats:

76% (01:44) correct 24% (02:01) wrong based on 109 sessions

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In the figure above, the point on segment PQ that is twice as far from P as from Q is

(A) (3,1)
(B) (2,1)
(C) (2,–1)
(D) (1.5, 0.5)
(E) (1,0)

Attachment:

2017-12-12_2124.png [ 8.75 KiB | Viewed 1560 times ]

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Joined: 14 Oct 2015
Posts: 236
GPA: 3.57
Re: In the figure above, the point on segment PQ that is twice as far from  [#permalink]

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13 Dec 2017, 21:58
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Bunuel wrote:

In the figure above, the point on segment PQ that is twice as far from P as from Q is

(A) (3,1)
(B) (2,1)
(C) (2,–1)
(D) (1.5, 0.5)
(E) (1,0)

Attachment:
2017-12-12_2124.png

It should be B.

x and y both change by 3. Traveling 2 from 0 and -1 (P) on both x and y axes would give us the point that is two times farther from P as it is from Q.
Intern
Joined: 03 May 2019
Posts: 5
Re: In the figure above, the point on segment PQ that is twice as far from  [#permalink]

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29 Aug 2019, 09:27
Any proper solution to this question?
Intern
Joined: 26 Aug 2018
Posts: 19
Re: In the figure above, the point on segment PQ that is twice as far from  [#permalink]

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03 Sep 2019, 17:01
Roosh18 wrote:
Any proper solution to this question?

Hi ,

The points can be found out by the section formula as below
P = (mx2+nx1/m+n , my2+ny1/m+n)
P= [(2*3 + 1*0 / 2+1), 2*2+1*-1 /2+1]
P= 2.1,1
Re: In the figure above, the point on segment PQ that is twice as far from   [#permalink] 03 Sep 2019, 17:01