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In the figure above, the radius of circle with center O is 1

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In the figure above, the radius of circle with center O is 1  [#permalink]

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New post 28 Jul 2018, 00:15
Hi Everyone,

Thanks for the very useful discussion here. I understood the property of diameter being the hypotenuse.
Please excuse my asking this extremely basic question (it must be a forgotten property), how do we know if the base is AB or BC?

Also, a super basic question for my learning.
Why are we taking hypotenuse = 1
Diameter is 2(r) = 2
Shouldn't we take:

1/2 *b*h
= 1/2 *sqrt(3) *2
= sqrt(3)

Thanks!
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Posts: 51035
Re: In the figure above, the radius of circle with center O is 1  [#permalink]

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New post 28 Jul 2018, 04:19
KungFuGmat wrote:
Hi Everyone,

Thanks for the very useful discussion here. I understood the property of diameter being the hypotenuse.
Please excuse my asking this extremely basic question (it must be a forgotten property), how do we know if the base is AB or BC?

Also, a super basic question for my learning.
Why are we taking hypotenuse = 1
Diameter is 2(r) = 2
Shouldn't we take:

1/2 *b*h
= 1/2 *sqrt(3) *2
= sqrt(3)

Thanks!


Your first doubt is addressed here: https://gmatclub.com/forum/in-the-figur ... l#p1803640

Your second doubt is not clear. The radius = 1, so the diameter, AC, which is also the hypotenuse is 2.
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Re: In the figure above, the radius of circle with center O is 1  [#permalink]

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New post 28 Jul 2018, 04:20
KungFuGmat wrote:
Hi Everyone,

Thanks for the very useful discussion here. I understood the property of diameter being the hypotenuse.
Please excuse my asking this extremely basic question (it must be a forgotten property), how do we know if the base is AB or BC?

Also, a super basic question for my learning.
Why are we taking hypotenuse = 1
Diameter is 2(r) = 2
Shouldn't we take:

1/2 *b*h
= 1/2 *sqrt(3) *2
= sqrt(3)

Thanks!


Your first doubt is addressed here: https://gmatclub.com/forum/in-the-figur ... l#p1803640 and here: https://gmatclub.com/forum/in-the-figur ... l#p2097597

Your second doubt is not clear. The radius = 1, so the diameter, AC, which is also the hypotenuse is 2.
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
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In the figure above, the radius of circle with center O is 1  [#permalink]

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New post 24 Nov 2018, 16:06
A video explanation can be found here:
https://www.youtube.com/watch?v=QjP0s-vOXLY

Three of the many equations and facts you'll need to memorize for the GMAT are

- Area of a triangle = 1/2(base)(height)

- In a right triangle with angles 30-60-90 degrees, if the leg opposite the 30 degree angle has length a, then the hypotenuse has a length of 2a, and the other leg has a length of a√3 (see video below)

https://www.youtube.com/watch?v=QjP0s-vOXLY

- If a triangle inscribed in a circle has the diameter of the circle as one of its sides, that side will always be the hypotenuse, and the two legs that touch the circumference of the crcle will always interesect at 90 degrees (also best explained in video below)

Here we have hypotenuse = 2, therefore base = 1 and height = √3, therefore area = 1/2(1)(√3) = √3/2

Answer B.
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In the figure above, the radius of circle with center O is 1 &nbs [#permalink] 24 Nov 2018, 16:06

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In the figure above, the radius of circle with center O is 1

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