It is currently 20 Oct 2017, 13:34

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

In the figure shown above, two identical squares are

Author Message
Manager
Joined: 28 Aug 2006
Posts: 143

Kudos [?]: 177 [0], given: 0

In the figure shown above, two identical squares are [#permalink]

Show Tags

09 Jun 2007, 19:52
1
This post was
BOOKMARKED
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

In the figure shown above, two identical squares are inscribed in the rectangle. If the perimeter of the rectangle is 18 by squareroot2, then what is the perimeter of each square?

(A) 8 by squareroot2
(B) 12
(C) 12 by squareroot2
(D) 16
(E) 18

OA will be posted next day
Attachments

Maths.jpg [ 5.85 KiB | Viewed 8097 times ]

Kudos [?]: 177 [0], given: 0

Director
Joined: 26 Feb 2006
Posts: 900

Kudos [?]: 157 [0], given: 0

Re: perimeter of each Square?? [#permalink]

Show Tags

09 Jun 2007, 20:16
humtum0 wrote:
In the figure shown above, two identical squares are inscribed in the rectangle. If the perimeter of the rectangle is 18 by squareroot2, then what is the perimeter of each square?

(A) 8 by squareroot2
(B) 12
(C) 12 by squareroot2
(D) 16
(E) 18

OA will be posted next day

B.
side of each square = x
diagnol of the square = hight of the rectangle = x sqrt(2)
length of the rectangle = 2 x sqrt(2)
perimeter of the rectangle = 2 [2 x sqrt(2) + x sqrt(2)]
18 sqrt(2) = 2 [2 x sqrt(2) + x sqrt(2)]
x = 3
perimeter of each square = 12

Kudos [?]: 157 [0], given: 0

CEO
Joined: 17 May 2007
Posts: 2947

Kudos [?]: 667 [0], given: 210

Show Tags

09 Jun 2007, 20:17
The answer is B - 12.

The key to understanding this problem is understanding that the length of the rectangle is twice the height (since 2 identical square are inscribed in it).

then its simple 2(2*h+ h ) = 18sqrt(2)
3h = 9sqrt(2)
h = 3sqrt(2)

Now h is also a diagonal of one of the squares.
if the length of the side of the square were x then according to isosceles triangle rule x + x = 3 sqrt(2) which means x = 3. For each inscribed square perimeter = 3 * 4 = 12. Hence option B.

ps. I am working under the assumption that "perimeter of the rectangle is 18 by squareroot2" implies 18*sqrt(2) not 18/sqrt(2). If I used 18/sqrt(2) I wouldnt get an answer in the selection.

Kudos [?]: 667 [0], given: 210

09 Jun 2007, 20:17
Display posts from previous: Sort by