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# In the figure, the radius of the circle with center O is 1

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Director
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In the figure, the radius of the circle with center O is 1 [#permalink]

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23 Jun 2007, 02:41
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In the figure, the radius of the circle with center O is 1 and BC =1. What is the area of the triangular region ABC?

A. sqrt(2)/2

B. sqrt(3)/2

C. 1

D. sqrt(2)

E. sqrt(3)
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Joined: 04 Jun 2007
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23 Jun 2007, 04:30
LM wrote:
In the figure, the radius of the circle with center O is 1 and BC =1. What is the area of the triangular region ABC?

A. sqrt(2)/2

B. sqrt(3)/2

C. 1

D. sqrt(2)

E. sqrt(3)

area = 0.5 * BC * AB (angle ABC is 90°) = 0.5 * 1 * sqrt(4-1)=0.5*sqrt(3)

Director
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23 Jun 2007, 04:47
Since AC is the diameter of the circle, angle ABC =90

AC=2
BC=1
=>AB=sqrt 3 (using pyth. th.)

Ar. = 1/2 bh = 1/2*1*sqrt 3 = (sqrt 3)/2

23 Jun 2007, 04:47
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