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In the graph above ,if divisions K and L togather
[#permalink]
Updated on: 31 Oct 2013, 02:44
Updated on: 31 Oct 2013, 02:44
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19%
(01:09)
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based on 272
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1)x=135
2)Profits contributed by division N are equal to half of the profits contributed by division L
Originally posted by guerrero25 on 30 Oct 2013, 23:01.
Last edited by guerrero25 on 31 Oct 2013, 02:44, edited 1 time in total.
Last edited by guerrero25 on 31 Oct 2013, 02:44, edited 1 time in total.
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Re: In the graph above ,if divisions K and L togather
[#permalink]
30 Oct 2013, 23:30
30 Oct 2013, 23:30
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Question :
K+L+M+N = 360
K+L = 180
M+N = 180
Find N
1) M=135. N can be found. Sufficient.
2) N = L/2. No idea about M. Insufficient.
Answer is A
K+L+M+N = 360
K+L = 180
M+N = 180
Find N
1) M=135. N can be found. Sufficient.
2) N = L/2. No idea about M. Insufficient.
Answer is A
Re: In the graph above ,if divisions K and L togather
[#permalink]
15 Jun 2018, 14:42
15 Jun 2018, 14:42
I got this wrong in my CAT...
My logic was this:
1) x =135
Since we know a circle is 360 degrees, and K and L contribute 50%, we have 180 degrees left. Since we are given the angle measure of X, we can solve for N
2) N = L/2
If K and L = 50%, then L must equal 90 degrees. If L is equal to 90 degrees, this would equal 25%. If N is half of L, then N = 12.5%
Am I missing something?...
My logic was this:
1) x =135
Since we know a circle is 360 degrees, and K and L contribute 50%, we have 180 degrees left. Since we are given the angle measure of X, we can solve for N
2) N = L/2
If K and L = 50%, then L must equal 90 degrees. If L is equal to 90 degrees, this would equal 25%. If N is half of L, then N = 12.5%
Am I missing something?...
