Author 
Message 
TAGS:

Hide Tags

Manager
Status: Never ever give up on yourself.Period.
Joined: 23 Aug 2012
Posts: 152
Location: India
Concentration: Finance, Human Resources
GMAT 1: 570 Q47 V21 GMAT 2: 690 Q50 V33
GPA: 3.5
WE: Information Technology (Investment Banking)

In the list above, k, m, and n are three distinct positive i [#permalink]
Show Tags
14 Jan 2013, 06:25
1
This post was BOOKMARKED
Question Stats:
53% (03:56) correct
47% (02:55) wrong based on 89 sessions
HideShow timer Statistics
3, k, 20, m, 4, n In the list above, k, m, and n are three distinct positive integers and the average (arithmetic mean) of the six numbers in the list is 8. If the median of the list is 6.5, which of the following CANNOT be the value of k, m, or n ? A.9 B.8 C.7 D.6 E.5 I didn't get the answer.My answer came out to be A.9..Help!!!!!!
Official Answer and Stats are available only to registered users. Register/ Login.
_________________
Don't give up on yourself ever. Period. Beat it, no one wants to be defeated (My journey from 570 to 690) : http://gmatclub.com/forum/beatitnoonewantstobedefeatedjourney570to149968.html



SDA Bocconi Thread Master
Joined: 27 Dec 2012
Posts: 36
Location: India
Concentration: Technology, Entrepreneurship
GMAT 1: 660 Q48 V33 GMAT 2: 730 Q49 V40
WE: Engineering (Energy and Utilities)

Re: In the list above, k, m, and n are three distinct positive i [#permalink]
Show Tags
14 Jan 2013, 13:15
1
This post received KUDOS
sum of all numbers = 8*6=48
and so k+m+n =21 (1)
in this list it can be safely assumed that 20 is the biggest number, because even if we assume 21 to be one of the nos, it would not satisfy the sum =48 condition.
median is (sum of middle two terms)/2, if no of terms is even.
So 3rd term + 4th term = 13 (2)
So we have to arrange the six number in increasing order. both 3 and 4 cannot be 3rd and 4th terms so that means, there is at max one term which is less than 3. So then there are two cases:
1st case. let us assume that k is less than 3: the order is k,3,4,m,n,20
4+m=13 from (2) m=9
so from(1) k+n=12 which means out of the five options 9 is already in. But since k is less than 3, the values of n would be either 11 or 12 (not in options)
2nd Case: if k is greater than 4
3,4,k,m,n,20
in this case k+m=13 and hence n = 8 now k is greater than 4, if k =5 then m=8 which cant be because already n=8 and as per question all k, m and n are distinct integers.
hence 5 cant be the choice.
DJ



Manager
Status: Never ever give up on yourself.Period.
Joined: 23 Aug 2012
Posts: 152
Location: India
Concentration: Finance, Human Resources
GMAT 1: 570 Q47 V21 GMAT 2: 690 Q50 V33
GPA: 3.5
WE: Information Technology (Investment Banking)

Re: In the list above, k, m, and n are three distinct positive i [#permalink]
Show Tags
14 Jan 2013, 18:48
DISTINCT...I missed this word...so i eliminated choice E,as I got the values 3458820 ,which had median as 6.5...thnks for the explaination...+1 Posted from my mobile device
_________________
Don't give up on yourself ever. Period. Beat it, no one wants to be defeated (My journey from 570 to 690) : http://gmatclub.com/forum/beatitnoonewantstobedefeatedjourney570to149968.html



Senior Manager
Joined: 20 Dec 2013
Posts: 267
Location: India

Re: In the list above, k, m, and n are three distinct positive i [#permalink]
Show Tags
28 Mar 2014, 07:13
Option E. Sum of 6 nos.=8*6=48 So k+m+n=4827=21 Also,median in case of even no. of terms=average of mid two terms=>6.5*2=13=third+fourth terms. Actually,when we take any of k,m,n to be 5,we get the other two values to be equal which is not possible since the question specifically asks for DISTINCT integers.



GMAT Club Legend
Joined: 09 Sep 2013
Posts: 15976

Re: In the list above, k, m, and n are three distinct positive i [#permalink]
Show Tags
26 May 2015, 04:09
Hello from the GMAT Club BumpBot! Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up  doing my job. I think you may find it valuable (esp those replies with Kudos). Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
GMAT Books  GMAT Club Tests  Best Prices on GMAT Courses  GMAT Mobile App  Math Resources  Verbal Resources



Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 7440
Location: Pune, India

Re: In the list above, k, m, and n are three distinct positive i [#permalink]
Show Tags
26 May 2015, 20:19
daviesj wrote: 3, k, 20, m, 4, n In the list above, k, m, and n are three distinct positive integers and the average (arithmetic mean) of the six numbers in the list is 8. If the median of the list is 6.5, which of the following CANNOT be the value of k, m, or n ?
A.9 B.8 C.7 D.6 E.5
I didn't get the answer.My answer came out to be A.9..Help!!!!!! I would use the method of elimination of options here since the question says "cannot be the value". All I have to do is prove that the rest of the options can be values of k, m and n. Since median is 6.5, the first options I will try are 6 and 7  two numbers will be eliminated if I can find a case where this works. 3, 4, 6, 7, 20  the avg of these numbers is 8. If the last number is also 8, the mean will remain 8 as desired. So in fact, we eliminated 3 options here. k, m and n can be 6, 7 and 8. Let's try 5 now, not 9 because 9 is more complicated. 9 gives us two number less than 6.5 and 2 more than 6.5. So there will be many different options. If instead 5 is in the list, we now have 3 numbers less than 6.5, so the other 3 numbers must be greater than 6.5 and the average of one of those numbers with 5 must be 6.5. So the fourth number should be 8 on the list to give the median 6.5. These 5 numbers (3, 4, 5, 8, 20) give an average of 8. The sixth number must be 8 to keep the average 8 but numbers must be distinct. So this is not possible. Hence none of k, m and n can be 5. Answer (E)
_________________
Karishma Veritas Prep  GMAT Instructor My Blog
Get started with Veritas Prep GMAT On Demand for $199
Veritas Prep Reviews




Re: In the list above, k, m, and n are three distinct positive i
[#permalink]
26 May 2015, 20:19








Similar topics 
Author 
Replies 
Last post 
Similar Topics:


1


The numbers m, n, and K are all positive integers. Given that m is a

Bunuel 
3 
15 Jan 2017, 02:07 

5


If m and n are positive integers, and m=2n and k=3m, then 

goodyear2013 
4 
28 Dec 2016, 10:47 

3


In the diagram above, ∠J = ∠M, ∠K = ∠N,

mikemcgarry 
3 
27 Mar 2015, 11:16 

3


The arithmetic mean of the list of numbers above is 4. If K and M are

Baten80 
4 
27 Jul 2016, 09:47 

44


If 5400mn = k^4, where m, n, and k are positive integers

banksy 
10 
28 Dec 2016, 10:33 



