In the multiplication above, each letter stands for a differ

A two digit number multiplied by another two digit number creating a 4 digit number. if we maximize one number to 99, we would realize that minimum value of another number would be atleast 11. (because 11*99 = 999). Further more A*B < 10
So we can list down the possible numbers.
13, 14, 15, 16, 17, 18, 19
20, 21, 22, 23, 24
30, 31, 32, 33
40, 41, 42
50, 51
60, 61
...

Now if we look at the options we would realize that only 23, 24, 32, 42 are in the options. So we can eliminate all other cases. Furthermore option C (25) is not in our list, so we can eliminate option C

Here we should understand that when AB is multiplied by CA, units digit is C which is also the value of A*B.

23 :- A = 2, B = 3, C = 6 (23*62) = --26 --------> Tens digit of four digit number (i.e.2) is not the same as B, Eliminate
32 :- A = 3, B = 2, C = 6 (32*63) = --16 --------> Tens digit of four digit number (i.e.1) is not the same as B, Eliminate
24 :- A = 2, B = 4, C = 8 (24*82) = --68 --------> Tens digit of four digit number (i.e.6) is not the same as B, Eliminate
42 :- A = 4, B = 2, C = 8 (42*84) = --28 --------> Tens digit of four digit number (i.e.6) is same as B, Bingo.. GO for Choice E