SajjadAhmad wrote:

In the Reagan High School swim club, 120 members swim the backstroke or the crawl or both. If 30 of these members do not swim the backstroke, how many members swim both the crawl and the backstroke?

(1) Of the 120 members, 72 do not swim the crawl.

(2) A total of 48 members swim the crawl.

Total members = 120

Numbers of member who do not swim backstroke = 30, so the numbers of member who swim backstroke = 120 - 30= 90

Statement 1: number of members who swim the crawl = 120 - 72 = 48

Therefore the numbers of members who crawl as well as backstroke = 90 + 48 - 120 = 18(sufficient)

Statement 2: from this statement we know the numbers of members swim the crawl = 48 , same as A we can derive the numbers who swim backstroke as well as crawl(sufficient)

Hence the correct answer D