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# In the rectangular coordinate system above, the shaded region is bound

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Math Expert
Joined: 02 Sep 2009
Posts: 50544
In the rectangular coordinate system above, the shaded region is bound  [#permalink]

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11 Dec 2017, 22:12
1
00:00

Difficulty:

45% (medium)

Question Stats:

80% (00:38) correct 20% (00:19) wrong based on 25 sessions

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In the rectangular coordinate system above, the shaded region is bounded by straight lines. Which of the following is NOT an equation of one of the boundary lines?

(A) x = 0
(B) y = 0
(C) x = 1
(D) x – y = 0
(E) x + 2y = 2

Attachment:

2017-12-12_1002_002.png [ 4.31 KiB | Viewed 475 times ]

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Joined: 22 May 2016
Posts: 2082
In the rectangular coordinate system above, the shaded region is bound  [#permalink]

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12 Dec 2017, 07:48
1
Bunuel wrote:

In the rectangular coordinate system above, the shaded region is bounded by straight lines. Which of the following is NOT an equation of one of the boundary lines?

(A) x = 0
(B) y = 0
(C) x = 1
(D) x – y = 0
(E) x + 2y = 2

Attachment:
2017-12-12_1002_002.png

Eliminate vertical and horizontal lines in Answers A, B, and C.

A is the y-axis, B is the x-axis, C, x=1, is the vertical line parallel to the y-axis. All are boundaries.

Answer D is correct. Rewrite as x = y. That line, nowhere to be seen, has a positive slope that runs at exactly 45° from the origin. It is not a boundary.

Answer E is the downward-sloped line, the boundary for the top of the enclosed region.

Rewrite E as y = $$-\frac{1}{2x}$$ + 1. Set x equal to zero: the y-intercept is 1. Correct. Set y equal to zero: the x-intercept is 2. Correct

In the rectangular coordinate system above, the shaded region is bound &nbs [#permalink] 12 Dec 2017, 07:48
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