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In the sequnce above, each term after the first 1/2 of the preceding term. What is the least term of the sequnce is greater than 1 ?

a 32/15 b 16/15 c 15/8 d 15/4 e 15/2

pleas help with a formula

There is no need for formula: 240, 120, 60, 30, 30/2, 30/4, 30/8, 30/16, 30/32<1. So the leas term more than 1 is 30/16=15/8.

But still if you need: \(\frac{30}{2^n}>1\), where n is integer --> \(2^n<30\) --> \(n<5\) --> \(n=4\) --> \(\frac{30}{2^n}=\frac{30}{2^4}=\frac{15}{8}\).

Re: In the sequence above, each term after the first 1/2 of the preceding [#permalink]

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29 Nov 2016, 07:36

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