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# In the sequence above, each term after the first 1/2 of the preceding

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Manager
Joined: 09 Jun 2010
Posts: 78
Followers: 1

Kudos [?]: 21 [1] , given: 17

In the sequence above, each term after the first 1/2 of the preceding [#permalink]

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29 Jul 2010, 23:37
1
KUDOS
1
This post was
BOOKMARKED
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Difficulty:

25% (medium)

Question Stats:

76% (01:47) correct 24% (00:57) wrong based on 21 sessions

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240,120,60,30

In the sequence above, each term after the first 1/2 of the preceding term. What is the least term of the sequence is greater than 1 ?

A. 32/15
B. 16/15
C. 15/8
D. 15/4
E. 15/2
[Reveal] Spoiler: OA
Math Expert
Joined: 02 Sep 2009
Posts: 38297
Followers: 7577

Kudos [?]: 103273 [0], given: 11369

Re: In the sequence above, each term after the first 1/2 of the preceding [#permalink]

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29 Jul 2010, 23:57
xmagedo wrote:
240,120,60,30

In the sequnce above, each term after the first 1/2 of the preceding term. What is the least term of the sequnce is greater than 1 ?

a 32/15
b 16/15
c 15/8
d 15/4
e 15/2

pleas help with a formula

There is no need for formula:
240, 120, 60, 30, 30/2, 30/4, 30/8, 30/16, 30/32<1. So the leas term more than 1 is 30/16=15/8.

But still if you need: $$\frac{30}{2^n}>1$$, where n is integer --> $$2^n<30$$ --> $$n<5$$ --> $$n=4$$ --> $$\frac{30}{2^n}=\frac{30}{2^4}=\frac{15}{8}$$.

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Kudos [?]: 190 [0], given: 0

Re: In the sequence above, each term after the first 1/2 of the preceding [#permalink]

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29 Nov 2016, 07:36
Hello from the GMAT Club BumpBot!

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Kudos [?]: 822 [0], given: 324

Re: In the sequence above, each term after the first 1/2 of the preceding [#permalink]

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29 Nov 2016, 09:19
xmagedo wrote:
240,120,60,30

In the sequence above, each term after the first 1/2 of the preceding term. What is the least term of the sequence is greater than 1 ?

A. 32/15
B. 16/15
C. 15/8
D. 15/4
E. 15/2

Greater than 1 = Numerator > Denominator

Now, go fearlessly- 30, 15 , 15/2 , 15/4 , 15/8, 15/16

Hence, the answer can be found in 10 seconds and it is (C)

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Abhishek....

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Re: In the sequence above, each term after the first 1/2 of the preceding   [#permalink] 29 Nov 2016, 09:19
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