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Re: In the table above, what is the least number of table entries that are [#permalink]

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15 Feb 2011, 21:32

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This post received KUDOS

Other than using combinations, you could see the chart has 6*6 = 36 entries. Diagonal is the distance from A to A, B to B etc so we can remove 6, leaving 30. Each has a duplicate so divide by 2 = 15

Re: In the table above, what is the least number of table entries that are [#permalink]

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19 Apr 2011, 20:16

Easy way to go about this problem is we have 6*6 = 36 enteries in table the least number of enteries would be (36 - 6) /2 since 6 enteries represent the distances between same points .

Alternatively this can be solved as combination problem.

Re: In the table above, what is the least number of table entries that are [#permalink]

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13 Jun 2017, 08:54

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In the table above, what is the least number of table entries that are needed to show the mileage between each city and each of the other five cities?

(A) 15 (B) 21 (C) 25 (D) 30 (E) 36

The least number of table entries will be if we use only one entry for each pair of the cities. How many entries would the table then have? Or how many different pairs can be selected out of 6 cities?