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In the triangle ABC in the file attached, AB is perpendicular to BC an

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Intern
Joined: 02 Jul 2010
Posts: 15
In the triangle ABC in the file attached, AB is perpendicular to BC an  [#permalink]

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26 Oct 2010, 12:59
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In the triangle ABC in the file attached, AB is perpendicular to BC and BD is perpendicular to DC.
What is the length of BD?

A/ 1
B/ 3/4
C/ 3/5
D/ sqrt(3)/5
E/ 3/10

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drawing.doc [22 KiB]

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Joined: 02 Sep 2010
Posts: 701
Location: London
Re: In the triangle ABC in the file attached, AB is perpendicular to BC an  [#permalink]

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26 Oct 2010, 14:40
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tatane90 wrote:
In the triangle ABC in the file attached, AB is perpendicular to BC and BD is perpendicular to DC.
What is the length of BD?

A/ 1
B/ 3/4
C/ 3/5
D/ sqrt(3)/5
E/ 3/10

Using pythogoras theorem, AC=sqrt(AB^2+BC^2)=sqrt(1+9/16)=5/4
Area of ABC = 0.5*AB*BC = 0.5*BD*AC
So, BD = (AB*BC)/AC = (3/4)/(5/4) = (3/5)

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Joined: 25 Aug 2010
Posts: 49
Re: In the triangle ABC in the file attached, AB is perpendicular to BC an  [#permalink]

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27 Oct 2010, 09:55
in the pic shown, 1/2*AB*BC = 1/2*BD*AC

ac^2 = ab^2 + bc^2 ===> ac = 5/4

( Since ABC and ACB vol are eq====> 3/4*1= BD* 5/4
====> BD = 3/5
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Re: In the triangle ABC in the file attached, AB is perpendicular to BC an  [#permalink]

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29 May 2019, 00:37
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Re: In the triangle ABC in the file attached, AB is perpendicular to BC an   [#permalink] 29 May 2019, 00:37