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In the triangle above, DC is parallel to AB. What is the len [#permalink]
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Urvasi wrote:
Bunuel wrote:
danzig wrote:


In the triangle above, DC is parallel to AB. What is the length of DC?

(1) AB = 14
(2) EC = CB

Please, confirm whether my solution is correct. If we consider both statements, we can notice that triangles AEB and DEC are the "same" triangle, except for the size. In other words, both have the same angles. Therefore, the relationship between any of two of their sides must be the same. Then,

\(\frac{14}{EB} = \frac{DC}{EC}\)

But we know that EC = 0.5*EB

Then: DC = 7

My answer is the OA.

Is it valid what I have done? I remember that I learned this in high school :s.


Yes, your solution is correct.

Else you can notice that DC is the midsegment (a line segment joining the midpoints of two sides of a triangle). The midsegment is always half the length of the third side, thus DC=AB/2=7.

Answer: C.

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Hope it's clear.


Is it ok to infer that DC is the mid segment? DC can be parallel without being mid segment; In that case the answer will change


We can deduce that DC is the midsegment only after we combine the statements. At that point we know that C is the midpoint of EB and DC is parallel to AB, therefore, DC must be the midsegment. When considering the statements alone DC may or may not be the midsegment.
GMAT Club Bot
In the triangle above, DC is parallel to AB. What is the len [#permalink]
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