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Re: In the triangle above, what is the length of the side BC? [#permalink]
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In my OG Quant 1 DAB=x.
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Re: In the triangle above, what is the length of the side BC? [#permalink]
walker wrote:
In my OG Quant 1 DAB=x.


Walker,

I checked it again, and I believe they have not published two versions of Quant-I (review). :shock:

The official guide, page number 193, shows that BDC = 2x and BCD = 2x.

That's why I thought somehow the explanation or rather the answer given in the OG is incorrect. :shock:
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Re: In the triangle above, what is the length of the side BC? [#permalink]
I think LM is right
Even in my quant, nothing is mentioned about angle DAB

explanation by OG - let angle DBA be y , so x + y = 2x (exterior angle) so x =y .........(but nowhere they mention that DAB is x)

Can official guide be wrong??? Surprise Surprise
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Re: In the triangle above, what is the length of the side BC? [#permalink]
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LM wrote:
Attachment:
Triangle.PNG

In the triangle above, what is the length of the side BC?

(1) Line segment AD has length 6
(2) x= 36

Can someone please explain the logic behind the explanation given in the official guide for the quantitative review-1st edition (question #117).

What I can't understand from the explanation is that it has been assumed that

angle ABD + angle DAB = 2x

will imply that ABD = DAB =x.

Why is the above true? Isn't it possible that ABD = 1.5x and DAB = 0.5x?

Why those two have to be equal?


PROPER VERSION OF THIS QUESTION IS HERE: in-triangle-abc-what-is-the-length-of-side-bc-106669.html

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