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# In the xy-coordinate plane, if the point (0,2) lies on the graph of th

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In the xy-coordinate plane, if the point (0,2) lies on the graph of th  [#permalink]

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25 Jun 2018, 05:07
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In the xy-coordinate plane, if the point (0,2) lies on the graph of the line 2x + ky = 4, what is the value of the constant k ?

A. 2

B. 1

C. 0

D. –1

E. –2

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Re: In the xy-coordinate plane, if the point (0,2) lies on the graph of th  [#permalink]

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25 Jun 2018, 05:24
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Bunuel wrote:
In the xy-coordinate plane, if the point (0,2) lies on the graph of the line 2x + ky = 4, what is the value of the constant k ?

A. 2

B. 1

C. 0

D. –1

E. –2

KEY CONCEPT: In order for a point to be ON a line, the x- and y-coordinates of the point must satisfy the equation of that line
So, for example, the point (3,7) lies ON the line defined by the equation y = 2x + 1, because x = 3 and y = 7 satisfy the equation y = 2x + 1
That is, 7 = 2(3) + 1

So, if the point (0,2) lies on the graph of the line 2x + ky = 4, then x = 0 and y = 2 must satisfy the equation 2x + ky = 4
Replace x and y with 0 and 2 to get: 2(0) + (k)(2) = 4
Simplify: 0 + 2k = 4
Solve: k = 2

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Re: In the xy-coordinate plane, if the point (0,2) lies on the graph of th  [#permalink]

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26 Jun 2018, 17:14
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Bunuel wrote:
In the xy-coordinate plane, if the point (0,2) lies on the graph of the line 2x + ky = 4, what is the value of the constant k ?

A. 2

B. 1

C. 0

D. –1

E. –2

Substituting 0 for x and 2 for y into the equation, we have:

2(0) + k(2) = 4

0 + 2k = 4

k = 2

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Re: In the xy-coordinate plane, if the point (0,2) lies on the graph of th  [#permalink]

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25 Jun 2018, 05:15
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Solution

Given:
• In the xy-coordinate plane, the point (0,2) lies on the graph of the line 2x + ky = 4

To find:
• The value of the constant k

Approach and Working:
As the point (0, 2) lies on the graph of the line 2x + ky = 4, it will satisfy the equation of the line

Therefore, we can write,
• 2 * 0 + k * 2 = 4
Or, 0 + 2k = 4
Or, 2k = 4
Or, k = 2

Hence, the correct answer is option A.

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Re: In the xy-coordinate plane, if the point (0,2) lies on the graph of th  [#permalink]

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16 Sep 2018, 14:02
1
Solution:

Step 1: If the point (0, 2) lies on the graph of the line 2x + ky = 4, then, the coordinate x = 0, y = 2 are a possible solution of the equation 2x + ky = 4.

Step 2: Following from Step 1 above, when x = 0 and y = 2, the equation 2x + ky = 4 becomes 2(0) + k(2) = 4. Hence, 0 + 2K = 4.

Therefore, k = 4/2 = 2. The answer is
Re: In the xy-coordinate plane, if the point (0,2) lies on the graph of th   [#permalink] 16 Sep 2018, 14:02
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