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In the xy-plane, line l and line k intersect at the point

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Manager
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Joined: 22 Jul 2008
Posts: 96

Kudos [?]: 241 [0], given: 11

Location: Bangalore,Karnataka
In the xy-plane, line l and line k intersect at the point [#permalink]

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New post 05 Jan 2010, 08:00
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Question Stats:

74% (00:42) correct 26% (01:10) wrong based on 100 sessions

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In the xy-plane, line l and line k intersect at the point (16/5, 12/5). What is the slope of line l?

(1) The product of the slopes of line l and line k is –1.
(2) Line k passes through the origin.
[Reveal] Spoiler: OA

Kudos [?]: 241 [0], given: 11

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P
Joined: 02 Aug 2009
Posts: 5212

Kudos [?]: 5851 [0], given: 117

Re: In the xy-plane, line l and line k intersect at the point [#permalink]

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New post 05 Jan 2010, 08:14
C..
si) gives us the relation in two lines ..the two r perpendicular to each other...not suff
sii) it gives us the 2nd pt on line k... we can find the slope of k from it but not l.. not suff.
combined frm k ,slope of l can be found frm reln in si..suff
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Kudos [?]: 5851 [0], given: 117

Manager
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Joined: 24 Aug 2016
Posts: 68

Kudos [?]: 19 [0], given: 24

Location: India
WE: Information Technology (Computer Software)
Re: In the xy-plane, line l and line k intersect at the point [#permalink]

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New post 04 Oct 2016, 22:50
Let equation of line l --> \(y = Lx + a\)
Let equation of line K --> \(y = Kx + b\)

Both line passes through (16/5, 12/5)

\(16L+5a = 12\) --Eq 1
\(16K+5b = 12\) --Eq2

(1) The product of the slopes of line l and line k is –1.

\(L * K=-1\) --Eq3

We have 3 equation and 4 unknown (a,b,L, M). -- Not sufficient

(2) Line k passes through the origin.

\(b = 0\)
\(16K+5b = 12\) ==> \(16K= 12\) ==> \(\frac{3}{4}\) -- Not sufficient


When we combine (1) and (2), L = -\(\frac{4}{3}\) --Sufficient.

Ans C.
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Kudos [?]: 19 [0], given: 24

Re: In the xy-plane, line l and line k intersect at the point   [#permalink] 04 Oct 2016, 22:50
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In the xy-plane, line l and line k intersect at the point

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