Bunuel wrote:
In the XY-plane, the vertices of a triangle have coordinates (0, 0), (5, 5) and (10, 0). What is the perimeter of the triangle?
(A) 12
(B) 13
(C) 5 + 10√2
(D) 10 + 5√2
(E) 10 + 10√2
Perimeter of the triangle = Sum of the lengths of three sides
\(Side_1\) = Distance between (0, 0), (5, 5) \(= √(5-0)^2+(5-0)^2 = √50 = 5√2\)
\(Side_2\) = Distance between (0, 0), (10, 0) \(= √(0-0)^2+(10-0)^2 = √100 = 10\)
\(Side_3\) = Distance between (10, 0), (5, 5) \(= √(5-0)^2+(5-10)^2 = √50 = 5√2\)
i.e. Perimeter \(= 5√2 + 5√2 + 10 = 10+10√2\)
Answer: Option E
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95% (01:20) correct 
