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In Town X, 64 percent of the population are employed, and 48 [#permalink]
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10 Apr 2016, 05:15
Walkabout wrote: In Town X, 64 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town X are females?
(A) 16% (B) 25% (C) 32% (D) 40% (E) 52% Plz anyone clear my highlighted confusion "In Town X, 64 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town X are females?" although i got 16 females were employed but what about rest 36% of population. . if it was written "What percent of the employed people in Town X are employed female" then i will consider 16/64... Plz clear my doubt... thanx...



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Re: In Town X, 64 percent of the population are employed, and 48 [#permalink]
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03 May 2016, 11:34
Walkabout wrote: In Town X, 64 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town X are females?
(A) 16% (B) 25% (C) 32% (D) 40% (E) 52% Let's use a convenient value for the total number of people in town X. Since this is a percent problem, 100 is an easy number to use. If there are 100 people in the town, we know: 100 x 0.64 = 64 = total employed 100 x 0.48 = 48 = employed males Thus, 64 – 48 = 16 employed females Now let's solve for the percent of employed people in town X who are females. [(Employed Females)/(Total Employed)] x 100 = 16/64 x 100 ¼ x 100 = 25% Answer B
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Re: In Town X, 64 percent of the population are employed, and 48 [#permalink]
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25 May 2016, 21:52
Attached is a visual that should help.
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Screen Shot 20160525 at 9.43.34 PM.png [ 150.16 KiB  Viewed 919 times ]
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Re: In Town X, 64 percent of the population are employed, and 48 [#permalink]
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26 May 2016, 04:18
Bunuel wrote: Walkabout wrote: In Town X, 64 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town X are females?
(A) 16% (B) 25% (C) 32% (D) 40% (E) 52% We are asked to find the percentage of females in employed people. Total employed people 64%, out of which 48 are employed males, hence 16% are employed females. (employed females)/(total employed people)=16/64=1/4=25% Answer: B. but female may be including unemployed females, the number of which we do not know. then how can we find the %.



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In Town X, 64 percent of the population are employed, and 48 [#permalink]
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26 May 2016, 04:33
robu wrote: Bunuel wrote: Walkabout wrote: In Town X, 64 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town X are females?
(A) 16% (B) 25% (C) 32% (D) 40% (E) 52% We are asked to find the percentage of females in employed people. Total employed people 64%, out of which 48 are employed males, hence 16% are employed females. (employed females)/(total employed people)=16/64=1/4=25% Answer: B. but female may be including unemployed females, the number of which we do not know. then how can we find the %. You should read a question and solution carefully. Given: 64 employed people ( employed females + employed males = 64); Out of 64 employed people, there are 48 employed males, thus employed females = total employed  employed males = 64  48 = 16. ( employed females)/(total employed people)=16/64=1/4=25%
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In Town X, 64 percent of the population are employed, and 48 [#permalink]
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26 May 2016, 05:14
Attachment:
Percentage Table.JPG [ 17.37 KiB  Viewed 887 times ]
First prepare a table like above. Given information is shaded in yellow. Let the total population is x. Then the total employed will be 0.64x. Also given: Employed males are 0.48 x. This will also be entered as shown above. Now we can easily calculate the employed females The value works out to (0.64 x  0.48x = 0.16x) We are simply asked: what is \(\frac{0.16x}{0.64x}\) in percentage terms. \(\frac{16}{64}\) is nothing but \(\frac{1}{4}\) = 25%Option B is the correct answer.



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In Town X, 64 percent of the population are employed, and 48 [#permalink]
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13 Jun 2016, 06:25
Solving the problem using tree structure
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Re: In Town X, 64 percent of the population are employed, and 48 [#permalink]
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13 Jun 2016, 06:29
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Walkabout wrote: In Town X, 64 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town X are females?
(A) 16% (B) 25% (C) 32% (D) 40% (E) 52% Reading question carefully is the key here 'What percent of the employed people in Town X are females' and not 'what percent of the total are employed females. Out of 64 employed people, 48 are males. Hence, 16 are females. 16 is 100*16/64= 25% of the employed people. B is the answer
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Re: In Town X, 64 percent of the population are employed, and 48 [#permalink]
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14 Oct 2016, 05:57
Walkabout wrote: In Town X, 64 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town X are females?
(A) 16% (B) 25% (C) 32% (D) 40% (E) 52% Let's use a convenient value for the total number of people in town X. Since this is a percent problem, 100 is an easy number to use. If there are 100 people in the town, we know: 100 x 0.64 = 64 = total employed 100 x 0.48 = 48 = employed males Thus, 64 – 48 = 16 employed females Now let's solve for the percent of employed people in town X who are females. [(Employed Females)/(Total Employed)] x 100 = 16/64 x 100 ¼ x 100 = 25% Answer B
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Re: In Town X, 64 percent of the population are employed, and 48 [#permalink]
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09 May 2018, 12:37
Walkabout wrote: In Town X, 64 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town X are females?
(A) 16% (B) 25% (C) 32% (D) 40% (E) 52% let total popoluation be X let total population be 100 hence > 64 people are employed 48 are employed employed females 6448=16 \(\frac{16}{64}\) * \(100%\) = \(25%\)




Re: In Town X, 64 percent of the population are employed, and 48
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