It is currently 10 Dec 2017, 19:14

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# In triangle ABC, point X is the midpoint of side AC and

 post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Current Student
Joined: 11 May 2008
Posts: 554

Kudos [?]: 232 [0], given: 0

In triangle ABC, point X is the midpoint of side AC and [#permalink]

### Show Tags

01 Aug 2008, 04:27
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

In triangle ABC, point X is the midpoint of side AC and point Y is the midpoint of side BC. If point R is the midpoint of line segment XC and if point S is the midpoint of line segment YC, what is the area of triangle region RCS
(1) the area of triangular region ABX is 32
(2) the length of one of the altitudes of triangle ABC is 8
A. Statement (1) ALONE is sufficient but Statement (2) ALONE is not sufficient.
B. Statement (2) ALONE is sufficient but Statement (1) ALONE is not sufficient.
C. BOTH Statements TOGETHER are sufficient, but NEITHER Statement alone is sufficient.
D. Each Statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.

Kudos [?]: 232 [0], given: 0

Current Student
Joined: 11 May 2008
Posts: 554

Kudos [?]: 232 [0], given: 0

Re: spoilt my head over this one [#permalink]

### Show Tags

01 Aug 2008, 04:45
hmmm, had got the same...

Kudos [?]: 232 [0], given: 0

Senior Manager
Joined: 16 Jul 2008
Posts: 288

Kudos [?]: 16 [1], given: 4

Re: spoilt my head over this one [#permalink]

### Show Tags

01 Aug 2008, 05:29
1
KUDOS
I am almost sure that the first statement is sufficient, but have no idea what to do with the second one... So I'd go for A
_________________

http://applicant.wordpress.com/

Kudos [?]: 16 [1], given: 4

VP
Joined: 17 Jun 2008
Posts: 1373

Kudos [?]: 430 [0], given: 0

Re: spoilt my head over this one [#permalink]

### Show Tags

02 Aug 2008, 23:53
arjtryarjtry wrote:
In triangle ABC, point X is the midpoint of side AC and point Y is the midpoint of side BC. If point R is the midpoint of line segment XC and if point S is the midpoint of line segment YC, what is the area of triangle region RCS
(1) the area of triangular region ABX is 32
(2) the length of one of the altitudes of triangle ABC is 8
A. Statement (1) ALONE is sufficient but Statement (2) ALONE is not sufficient.
B. Statement (2) ALONE is sufficient but Statement (1) ALONE is not sufficient.
C. BOTH Statements TOGETHER are sufficient, but NEITHER Statement alone is sufficient.
D. Each Statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.

IMO A
given that RCS is similar to YXC ,YXC is similar to BCX which is similar to ABC.
(1) gives area of ABX which can be used to get area of RCS since these are all similar triangles
(2) does not indicate are but just the altitude hence cant help in finding are of RCS

(1) is suffi and (2) is not

IMO A
_________________

cheers
Its Now Or Never

Kudos [?]: 430 [0], given: 0

Manager
Joined: 09 Jul 2007
Posts: 244

Kudos [?]: 278 [0], given: 0

Re: spoilt my head over this one [#permalink]

### Show Tags

05 Aug 2008, 16:21
IMO A .
Reason : as ACB and RCS are symitrical triangles, there sides will be proportionate ( ratio 1:4 ).. and so area will be also propotionate , but with a square.. i.e 1: 16.. as the area of ACB is 64 as per statement 1, the area of RCS it bill be 4.
statement 2 is not sufficient as the altitue can be any of the 3.

Kudos [?]: 278 [0], given: 0

Retired Moderator
Joined: 18 Jul 2008
Posts: 959

Kudos [?]: 312 [0], given: 5

Re: spoilt my head over this one [#permalink]

### Show Tags

05 Aug 2008, 18:01
Question on similar triangles -

What are the requirements? I thought you needed two angles to tell that 2 triangles are similar?

Kudos [?]: 312 [0], given: 5

SVP
Joined: 07 Nov 2007
Posts: 1790

Kudos [?]: 1101 [0], given: 5

Location: New York
Re: spoilt my head over this one [#permalink]

### Show Tags

06 Aug 2008, 10:13
spriya wrote:
arjtryarjtry wrote:
In triangle ABC, point X is the midpoint of side AC and point Y is the midpoint of side BC. If point R is the midpoint of line segment XC and if point S is the midpoint of line segment YC, what is the area of triangle region RCS
(1) the area of triangular region ABX is 32
(2) the length of one of the altitudes of triangle ABC is 8
A. Statement (1) ALONE is sufficient but Statement (2) ALONE is not sufficient.
B. Statement (2) ALONE is sufficient but Statement (1) ALONE is not sufficient.
C. BOTH Statements TOGETHER are sufficient, but NEITHER Statement alone is sufficient.
D. Each Statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.

IMO A
given that RCS is similar to YXC ,YXC is similar to BCX which is similar to ABC.
(1) gives area of ABX which can be used to get area of RCS since these are all similar triangles
(2) does not indicate are but just the altitude hence cant help in finding are of RCS

(1) is suffi and (2) is not

IMO A

How come BCX similar to ABC?
I agree that RCS is similar to ABC.

Given ABX=32.. is it possible to find ABC area?
_________________

Smiling wins more friends than frowning

Kudos [?]: 1101 [0], given: 5

Senior Manager
Joined: 31 Jul 2008
Posts: 290

Kudos [?]: 57 [0], given: 0

Re: spoilt my head over this one [#permalink]

### Show Tags

06 Aug 2008, 15:22
Here the triangles are similar as :

1 vertex (angle is common)
2 base is parallel (which suggests equal angles)

Hence A shud be the choice

Kudos [?]: 57 [0], given: 0

SVP
Joined: 07 Nov 2007
Posts: 1790

Kudos [?]: 1101 [0], given: 5

Location: New York
Re: spoilt my head over this one [#permalink]

### Show Tags

07 Aug 2008, 07:44
stallone wrote:
Here the triangles are similar as :

1 vertex (angle is common)
2 base is parallel (which suggests equal angles)

Hence A shud be the choice

I agree that triangle ABC is similar to triangle RCS.

But ABX is not similar to RCS.

my question is in statement 1 given ABX area not ABC.
to find the RCS we need ABC are which is similar to RCS

am i missing something???
_________________

Smiling wins more friends than frowning

Kudos [?]: 1101 [0], given: 5

Intern
Joined: 22 Jul 2008
Posts: 44

Kudos [?]: 16 [0], given: 0

Re: spoilt my head over this one [#permalink]

### Show Tags

07 Aug 2008, 10:08
In an earlier reply :
given that RCS is similar to YXC ,YXC is similar to BCX which is similar to ABC.
(1) gives area of ABX which can be used to get area of RCS since these are all similar triangles
(2) does not indicate are but just the altitude hence cant help in finding are of RCS

HOW does YXC be similiar to BCX and ABX to RCS

I am confused

Kudos [?]: 16 [0], given: 0

Intern
Joined: 07 Aug 2008
Posts: 2

Kudos [?]: [0], given: 0

Re: spoilt my head over this one [#permalink]

### Show Tags

07 Aug 2008, 10:43
option 1 is sufficient.

From the area of ABX, we can find the area of RCS, so statement "1" is sufficient

Kudos [?]: [0], given: 0

SVP
Joined: 07 Nov 2007
Posts: 1790

Kudos [?]: 1101 [0], given: 5

Location: New York
Re: spoilt my head over this one [#permalink]

### Show Tags

07 Aug 2008, 12:53
farrukhiq wrote:
option 1 is sufficient.

From the area of ABX, we can find the area of RCS, so statement "1" is sufficient

Can you exlaborate how to find RCS from ABX
_________________

Smiling wins more friends than frowning

Kudos [?]: 1101 [0], given: 5

Manager
Joined: 08 Aug 2008
Posts: 229

Kudos [?]: 54 [0], given: 0

Re: spoilt my head over this one [#permalink]

### Show Tags

08 Aug 2008, 06:46
agreed RCS similar to ABC....but ABX cannot be concluded to be simlar to ABC.
1) altitude BX
2)AX=1/2AC
3)angle?

/_A cant be considered as there is no SSA or ASS similarity.
please correct me if im missing something else.....

Kudos [?]: 54 [0], given: 0

Re: spoilt my head over this one   [#permalink] 08 Aug 2008, 06:46
Display posts from previous: Sort by

# In triangle ABC, point X is the midpoint of side AC and

 post reply Question banks Downloads My Bookmarks Reviews Important topics

Moderator: chetan2u

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.