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# In what ratio must a person mix three kinds of tea costing Rs.60/kg, R

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Math Expert
Joined: 02 Sep 2009
Posts: 64096
In what ratio must a person mix three kinds of tea costing Rs.60/kg, R  [#permalink]

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29 Jan 2019, 07:18
00:00

Difficulty:

55% (hard)

Question Stats:

62% (02:44) correct 38% (02:57) wrong based on 74 sessions

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In what ratio must a person mix three kinds of tea costing Rs.60/kg, Rs.75/kg and Rs.100 /kg so that the resultant mixture when sold at Rs.96/kg yields a profit of 20%?

A. 1 : 2 : 4
B. 3 : 7 : 6
C. 1 : 4 : 2
D. 1 : 4 : 3
E. 1 : 4 : 4

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Re: In what ratio must a person mix three kinds of tea costing Rs.60/kg, R  [#permalink]

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29 Jan 2019, 09:57
1
Bunuel wrote:
In what ratio must a person mix three kinds of tea costing Rs.60/kg, Rs.75/kg and Rs.100 /kg so that the resultant mixture when sold at Rs.96/kg yields a profit of 20%?

A. 1 : 2 : 4
B. 3 : 7 : 6
C. 1 : 4 : 2
D. 1 : 4 : 3
E. 1 : 4 : 4

given cost 96 per kg rate & profit 20 % so actual price : 96/1.2 = 80

option C
1*60+ 4*75+2*100 /(1+4+2) = 560 / 7 = 80 which is our original price
sufficient
IMO C
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Re: In what ratio must a person mix three kinds of tea costing Rs.60/kg, R  [#permalink]

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29 Jan 2019, 10:18
Bunuel wrote:
In what ratio must a person mix three kinds of tea costing Rs.60/kg, Rs.75/kg and Rs.100 /kg so that the resultant mixture when sold at Rs.96/kg yields a profit of 20%?

A. 1 : 2 : 4
B. 3 : 7 : 6
C. 1 : 4 : 2
D. 1 : 4 : 3
E. 1 : 4 : 4

I found this approach fool proof

Resultant mixture : x+y+z

SP = CP + 0.20 CP
SP = 1.2CP

1.2 * (60 x + 75y + 100z) = 96 ( x+y+z)
60 x + 75y + 100z = 80 x + 80y + 80 z

20z = 20 x + 5y

4z = 4x + y

No just put back the ratios to check the value, Only C satisfies

8 = 4 + 4
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Re: In what ratio must a person mix three kinds of tea costing Rs.60/kg, R   [#permalink] 29 Jan 2019, 10:18