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# Inequality Question

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Intern
Joined: 03 Feb 2009
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03 Feb 2009, 14:14
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Which of the following inequalities has a solution set that, when graphed on a number line, is a single line segment of finite length?

A) x^4 >= 1
B) x^3 <= 27
C) x^2 >= 16
D) 2 <= abs(x) <= 5
E) 2 <= 3x +4 <= 6

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SVP
Joined: 07 Nov 2007
Posts: 1792

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Location: New York

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03 Feb 2009, 21:22
bmiller0731 wrote:
Which of the following inequalities has a solution set that, when graphed on a number line, is a single line segment of finite length?

A) x^4 >= 1
B) x^3 <= 27
C) x^2 >= 16
D) 2 <= abs(x) <= 5
E) 2 <= 3x +4 <= 6

should be E

All other options have multiple solutions which are discrete

2 <= 3x +4 <= 6

-->
-2/3<=x<=2/3

join points..

it is straight line and finite length starting -2/3 and ending at 2/3
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Intern
Joined: 15 Jan 2009
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04 Feb 2009, 07:32
Why isn't x^3<=27 the answer? Shouldn't the answer for b equal to x <=3?

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04 Feb 2009, 08:17
wcgmatclub wrote:
Why isn't x^3<=27 the answer? Shouldn't the answer for b equal to x <=3?

question says segment of finite length

x<=3.. means x can be -infinity..
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Joined: 29 Aug 2007
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04 Feb 2009, 09:25
x2suresh wrote:
bmiller0731 wrote:
Which of the following inequalities has a solution set that, when graphed on a number line, is a single line segment of finite length?

A) x^4 >= 1
B) x^3 <= 27
C) x^2 >= 16
D) 2 <= abs(x) <= 5
E) 2 <= 3x +4 <= 6

should be E

All other options have multiple solutions which are discrete

2 <= 3x +4 <= 6

-->
-2/3<=x<=2/3

join points..

it is straight line and finite length starting -2/3 and ending at 2/3

Agree with above.

Edited...
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Kudos [?]: 843 [0], given: 19

SVP
Joined: 07 Nov 2007
Posts: 1792

Kudos [?]: 1061 [0], given: 5

Location: New York

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04 Feb 2009, 09:31
GMAT TIGER wrote:
x2suresh wrote:
bmiller0731 wrote:
Which of the following inequalities has a solution set that, when graphed on a number line, is a single line segment of finite length?

A) x^4 >= 1
B) x^3 <= 27
C) x^2 >= 16
D) 2 <= abs(x) <= 5
E) 2 <= 3x +4 <= 6

should be E

All other options have multiple solutions which are discrete

2 <= 3x +4 <= 6

-->
-2/3<=x<=2/3

join points..

it is straight line and finite length starting -2/3 and ending at 2/3

Agree with above.
Small typo: it is straight line and finite length starting -2/3 and ending at 3/2.

2 <= 3x +4 <= 6
--> -2<=3x<=2
--> -2/3<=x<=2/3
_________________

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Kudos [?]: 1061 [0], given: 5

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Posts: 2472

Kudos [?]: 843 [0], given: 19

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04 Feb 2009, 09:41
x2suresh wrote:
2 <= 3x +4 <= 6
--> -2<=3x<=2
--> -2/3<=x<=2/3

Agree with you and I editerd my post too. I considered only 4. Sorry about that.

You rock, x2suresh.
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Re: Inequality Question   [#permalink] 04 Feb 2009, 09:41
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