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IR Practice Exam 4 Question 3

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IR Practice Exam 4 Question 3 [#permalink]

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New post 20 Feb 2015, 10:53
Please advice me on how to proceed with this particular question.
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Re: IR Practice Exam 4 Question 3 [#permalink]

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New post 20 Feb 2015, 12:54
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You did this correctly. If Francois = F and Pierre = P, then...

\(.5F + .1P = .4(F+P)\)

\(.5F + .1P = .4F + .4P\)

\(.1F = .3P\) or \(F = 3P\)

You must select the right combination of answer choices that make this statement true.
Only €750 and €250 make this possible.

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Re: IR Practice Exam 4 Question 3 [#permalink]

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New post 20 Feb 2015, 14:31
Thank you for a prompt and informative reply. I had the right approach, but did a careless mistake. Many thanks again!

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Re: IR Practice Exam 4 Question 3 [#permalink]

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New post 03 Jan 2017, 17:30
Here's what I'm not understanding...

If Francois pays out $750, then he owes $1,500. ($750 is 50% of $1,500).
If Pierre pays out $250, then he owes $2,500. ($250 is 10% of $2,500).

Together, Francois and Pierre pay out a total of $1,000. However, they owe Claudine a total of $4,000 ($1,500 + $2,500). $1,000 is not 40% of $4,000.

Now, if you use $750 for Francois and only $50 for Pierre, the math works out as follows:

Total Payment = 750 + 50 = 800
Total Owed = 1500 + 500 = 2000

And $800 is 40% of $2,000.

Could someone PLEASE shed some light. I've been tinkering over this problem for the past hour. :(

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Re: IR Practice Exam 4 Question 3 [#permalink]

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New post 04 Feb 2017, 12:59
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0.5 F + 0.1 P = 0.4 (F + P)
If F owes 750 then he pays 750*0.5 = 375
if P owes 250 then he pays 250*0.1 = 25
Total = 375 + 25 = 400
Now 40 % of combined= 0.4 * (750 + 250) = 400
Both are same.

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Re: IR Practice Exam 4 Question 3   [#permalink] 04 Feb 2017, 12:59
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