Bunuel wrote:
Is 0 < m < 1?
(1) m^2 is less than 1.
(2) m^2 < m
We need to determine whether m is between 0 and 1.
Statement One Alone:
m^2 is less than 1
We can simplify the information in statement one:
m^2 < 1
√m^2 < √1
Thus:
m < 1
or
-m < 1
m > -1
That is, -1 < m < 1. Thus, m is not necessarily between 0 and 1, since m could be between 0 and -1.
Statement one is not sufficient to answer the question.
Statement Two Alone:
m^2 < m
Since m^2 is less than m, the only values that satisfy such an inequality are when m is between 0 and 1. Thus, statement two is sufficient to answer the question.
Answer: B
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