It is currently 24 Nov 2017, 04:29

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

Is 0<x<1? (I) x^2 < x^{1/3} (II) x^3<x^{1/3

Author Message
SVP
Joined: 03 Jan 2005
Posts: 2228

Kudos [?]: 386 [0], given: 0

Is 0<x<1? (I) x^2 < x^{1/3} (II) x^3<x^{1/3 [#permalink]

Show Tags

24 Jan 2005, 22:39
00:00

Difficulty:

(N/A)

Question Stats:

33% (02:18) correct 67% (02:32) wrong based on 10 sessions

HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Is 0<x<1?

(I)$$x^2 < x^{1/3}$$
(II)$$x^3<x^{1/3}$$

Kudos [?]: 386 [0], given: 0

VP
Joined: 25 Nov 2004
Posts: 1481

Kudos [?]: 131 [0], given: 0

Show Tags

24 Jan 2005, 23:07
i think A.
statement i is suff.......... and statement ii is not suff...

Kudos [?]: 131 [0], given: 0

Senior Manager
Joined: 19 Nov 2004
Posts: 281

Kudos [?]: 48 [0], given: 0

Location: Germany

Show Tags

25 Jan 2005, 07:37
Is it (D)?

Is 0<x<1?

(I)x^2 < x^(1/3) - raise both sides to the power 3: x^2/3 < x

(II)x^3<x^(1/3) - same: raise both sides to the power of 3: x^9 < x

Kudos [?]: 48 [0], given: 0

Current Student
Joined: 28 Dec 2004
Posts: 3345

Kudos [?]: 323 [0], given: 2

Location: New York City
Schools: Wharton'11 HBS'12

Show Tags

25 Jan 2005, 08:27
I go for D

that is if negative numbers are allowed! in that case we have an imaginary numbers, then in that case its A

Kudos [?]: 323 [0], given: 2

VP
Joined: 18 Nov 2004
Posts: 1430

Kudos [?]: 49 [0], given: 0

Show Tags

25 Jan 2005, 08:44
"A" for me.

state 1: x = 1/8....satisfies.....x = -1/8 doesn't ....so x has to be between 0 and 1...suff.

state 2: x = 1/8....satisfies....x = -8...satisfies....insuff.

Kudos [?]: 49 [0], given: 0

Intern
Joined: 25 Jan 2005
Posts: 13

Kudos [?]: [0], given: 0

Show Tags

25 Jan 2005, 19:18
Is 0<x<1?

(I)x^2 < x^(1/3)
(II)x^3<x^(1/3)

for 0<x<1 , in either cases cubing the inequations will help.
on cubing, (I) becomes x^6 < x which is true for all 0< x< 1
(II) becomes x^9 < x which agian is true but almost a repetition of (I) . Therefore (I) alone is sufficient .

Kudos [?]: [0], given: 0

Director
Joined: 25 Jan 2004
Posts: 721

Kudos [?]: 32 [0], given: 0

Location: Milwaukee

Show Tags

25 Jan 2005, 22:37
In this case don't you think D should be the answer??

vsom wrote:
Is 0<x<1?

(I)x^2 < x^(1/3)
(II)x^3<x^(1/3)

for 0<x<1 , in either cases cubing the inequations will help.
on cubing, (I) becomes x^6 < x which is true for all 0< x< 1
(II) becomes x^9 < x which agian is true but almost a repetition of (I) . Therefore (I) alone is sufficient .

_________________

Praveen

Kudos [?]: 32 [0], given: 0

Manager
Joined: 19 Nov 2004
Posts: 59

Kudos [?]: 7 [0], given: 0

Show Tags

26 Jan 2005, 00:51
A
x^9<x is true not only for 0<x<1, but also for x<-1 that's why 2) Insuff

Kudos [?]: 7 [0], given: 0

Intern
Joined: 26 Jan 2005
Posts: 11

Kudos [?]: [0], given: 0

Show Tags

26 Jan 2005, 07:24
I guess the question of -ve numbers doesnt arise. We have to assume real numbers only. And in that case, statement 1 is sufficient. No need for statement 2. But isnt statement 2 sufficient by itself too? Any comments?

Kudos [?]: [0], given: 0

SVP
Joined: 03 Jan 2005
Posts: 2228

Kudos [?]: 386 [0], given: 0

Show Tags

26 Jan 2005, 09:17
II is not sufficient, x could be positive or negative.

Kudos [?]: 386 [0], given: 0

Manager
Joined: 28 Jul 2004
Posts: 58

Kudos [?]: [0], given: 0

Location: Na

Show Tags

31 Jan 2005, 05:31
Banerjee,

Can you let me know how you chose the numbers?What are your considerations for choosing the numbers?Thank you.Rgds

Anna

banerjeea_98 wrote:
"A" for me.

state 1: x = 1/8....satisfies.....x = -1/8 doesn't ....so x has to be between 0 and 1...suff.

state 2: x = 1/8....satisfies....x = -8...satisfies....insuff.

_________________

We can crack the exam together

Kudos [?]: [0], given: 0

31 Jan 2005, 05:31
Display posts from previous: Sort by