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# Is 1/ ( a-b ) < b-a? 1. a<b 2.1<|a-b

Author Message
Manager
Joined: 20 Nov 2004
Posts: 108

Kudos [?]: 3 [0], given: 0

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13 Apr 2006, 08:50
chiragr wrote:
so a-b is negative and b-a is positive
=> 1/a-b is negative and b-a is positive

H E L P

Am I the only one who thinks that it's a major difference if it's
1/a-b OR
1/(a-b)

I'm sorry, but the question tells us that it's
1/a-b = (1/a) - b
AND NOT
1 / (a-b)
.

The problem is, that this - besides the math - leads to another answer,
which is E.

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SVP
Joined: 03 Jan 2005
Posts: 2227

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13 Apr 2006, 12:30
Here's my solution. I only have 1 minute so please let me know if the logic is not correct.

We want to know if 1/(a-b)<b-a

In other words if (b-a)-1/(a-b)>0
or if (-(a-b)^2-1)/(a-b)>0

We can see that the numerator is definitely negative. So the only thing we need to know is if a-b>0

2) a-b could be negative or positive. Thus insufficent.

_________________

Keep on asking, and it will be given you;
keep on seeking, and you will find;
keep on knocking, and it will be opened to you.

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Manager
Joined: 20 Nov 2004
Posts: 108

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13 Apr 2006, 12:40
HongHu wrote:
I only have 1 minute so please let me know if the logic is not correct.

Well done for a minute and the logic IS correct

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Manager
Joined: 08 Feb 2006
Posts: 124

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13 Apr 2006, 12:48
I got A.

Statement 2 is not sufficient.

I tried a=4, b=1 which did not satisfy both equations.
Next, I tried a=-2, b=2, which satisfied both equations.

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13 Apr 2006, 12:48

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