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Is -1<x<0?

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Director
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GMAT 1: 460 Q42 V13
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Is -1<x<0?  [#permalink]

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New post 02 Mar 2019, 09:56
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Difficulty:

  65% (hard)

Question Stats:

46% (01:51) correct 54% (01:28) wrong based on 39 sessions

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Is -1<x<0?

I. x^3 >-1
II. x^2-1<0
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Re: Is -1<x<0?  [#permalink]

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New post 02 Mar 2019, 19:26
1
From statement 1:

x^3 > -1.
Means x > -1.
But no info whether x is less than 0.
Hence Insufficient.

From statement 2:

x^-1<0
Or -1<x<1.
Again x >-1. But no info whether x is less than 0.
Hence Insufficient.

Combining both also gives no extra info.
Hence E is the answer
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Director
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Re: Is -1<x<0?  [#permalink]

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New post 02 Mar 2019, 20:25
Afc0892 wrote:
From statement 1:

x^3 > -1.
Means x > -1.
But no info whether x is less than 0.
Hence Insufficient.

From statement 2:

x^-1<0
Or -1<x<1.
Again x >-1. But no info whether x is less than 0.
Hence Insufficient.

Combining both also gives no extra info.
Hence E is the answer


Hi,
Thanks for the explanation. I am in a little confusion in Statment 2. Can you please explain Statment 2 more elaborately
Intern
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Is -1 [#permalink]

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New post 02 Mar 2019, 20:36
1
x^2-1<0
(x+1)(x-1)<0
-1<x<1

Now this gives range for x which is higher than the given in the question, so we cannot say it this statement is sufficient. Hence insufficient.


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Re: Is -1<x<0?  [#permalink]

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New post 02 Mar 2019, 21:10
kiran120680 wrote:
Afc0892 wrote:
From statement 1:

x^3 > -1.
Means x > -1.
But no info whether x is less than 0.
Hence Insufficient.

From statement 2:

x^-1<0
Or -1<x<1.
Again x >-1. But no info whether x is less than 0.
Hence Insufficient.

Combining both also gives no extra info.
Hence E is the answer


Hi,
Thanks for the explanation. I am in a little confusion in Statment 2. Can you please explain Statment 2 more elaborately



We have a formula for thia inequality

x^2 - a^2 <0

IT MEANS -a<x<a

this formula is used in second statement

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Re: Is -1<x<0?   [#permalink] 02 Mar 2019, 21:10
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