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# Is 2(a+b-c) an odd integer? 1. a, b and c are consecutive

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Is 2(a+b-c) an odd integer? 1. a, b and c are consecutive [#permalink]

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07 May 2010, 10:32
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Is 2(a+b-c) an odd integer?

1. a, b and c are consecutive numbers
2. b=a+c

The OA is A. But, I think it is incorrect.
Case1: 0,1,2 the a+b-c = -1 (Yes)
Case2: 1,2,3 the a+b-c = 0 (No)

Can someone tell me where I am wrong?
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Re: GmatClub Test: Number Properies - I (DS) [#permalink]

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07 May 2010, 11:21
ykaiim wrote:
Is 2(a+b-c) an odd integer?

1. a, b and c are consecutive numbers
2. b=a+c

The OA is A. But, I think it is incorrect.
Case1: 0,1,2 the a+b-c = -1 (Yes)
Case2: 1,2,3 the a+b-c = 0 (No)

Can someone tell me where I am wrong?

You forgot to multiply the -1 by 2

2(a+b-c)
2(0+1-2)
2(-1) = -2

or 2a + 2b - 2c
2(0) + 2(1) - 2(2)
2-4 = -2

Is the question correct? Multiplying anything by 2 will never give an odd so the question states the answer. In which case you wouldn't need to test 1 or 2

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Re: GmatClub Test: Number Properies - I (DS) [#permalink]

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07 May 2010, 17:07
lagomez wrote:
ykaiim wrote:
Is 2(a+b-c) an odd integer?

1. a, b and c are consecutive numbers
2. b=a+c

The OA is A. But, I think it is incorrect.
Case1: 0,1,2 the a+b-c = -1 (Yes)
Case2: 1,2,3 the a+b-c = 0 (No)

Can someone tell me where I am wrong?

You forgot to multiply the -1 by 2

2(a+b-c)
2(0+1-2)
2(-1) = -2

or 2a + 2b - 2c
2(0) + 2(1) - 2(2)
2-4 = -2

Is the question correct? Multiplying anything by 2 will never give an odd so the question states the answer. In which case you wouldn't need to test 1 or 2

I agree with lagomez. any number x 2 = Even
Something must be wrong

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Re: GmatClub Test: Number Properies - I (DS) [#permalink]

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07 May 2010, 18:11
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ykaiim wrote:
Is 2(a+b-c) an odd integer?

1. a, b and c are consecutive numbers
2. b=a+c

The OA is A. But, I think it is incorrect.
Case1: 0,1,2 the a+b-c = -1 (Yes)
Case2: 1,2,3 the a+b-c = 0 (No)

Can someone tell me where I am wrong?

$$2(a+b-c)$$ can be:
odd, in case $$a+b-c=\frac{odd}{2}$$;
even, in case $$a+b-c=integer$$
not an integer at all, in case $$a+b-c$$ does not equal to any above. For example: $$a+b-c=\sqrt{2}$$ or $$a+b-c=0.3$$.

Guess statement (1) is saying: "a, b and c are consecutive integers". The word "consecutive" is redundant here. Just knowing that "a, b and c are integers" is enough to say that this statement is sufficient to answer the question. And the answer would be NO: a, b and c are integers --> $$a+b-c=integer$$ --> $$2(a+b-c)=even$$.

Statement (2) is clearly not sufficient.
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Re: GmatClub Test: Number Properies - I (DS) [#permalink]

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07 May 2010, 18:31
Bunuel wrote:
ykaiim wrote:
Is 2(a+b-c) an odd integer?

1. a, b and c are consecutive numbers
2. b=a+c

The OA is A. But, I think it is incorrect.
Case1: 0,1,2 the a+b-c = -1 (Yes)
Case2: 1,2,3 the a+b-c = 0 (No)

Can someone tell me where I am wrong?

$$2(a+b-c)$$ can be:
odd, in case $$a+b-c=\frac{odd}{2}$$;
even, in case $$a+b-c=integer$$
not an integer at all, in case $$a+b-c$$ does not equal to any above. For example: $$a+b-c=\sqrt{2}$$ or $$a+b-c=0.3$$.

Guess statement (1) is saying: "a, b and c are consecutive integers". The word "consecutive" is redundant here. Just knowing that "a, b and c are integers" is enough to say that this statement is sufficient to answer the question. And the answer would be NO: a, b and c are integers --> $$a+b-c=integer$$ --> $$2(a+b-c)=even$$.

Statement (2) is clearly not sufficient.

What numbers can be substituted for A, B, and C and when multiplied by 2 gives you an odd integer?

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Re: GmatClub Test: Number Properies - I (DS) [#permalink]

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07 May 2010, 18:49
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lagomez wrote:
Bunuel wrote:
ykaiim wrote:
Is 2(a+b-c) an odd integer?

1. a, b and c are consecutive numbers
2. b=a+c

The OA is A. But, I think it is incorrect.
Case1: 0,1,2 the a+b-c = -1 (Yes)
Case2: 1,2,3 the a+b-c = 0 (No)

Can someone tell me where I am wrong?

$$2(a+b-c)$$ can be:
odd, in case $$a+b-c=\frac{odd}{2}$$;
even, in case $$a+b-c=integer$$
not an integer at all, in case $$a+b-c$$ does not equal to any above. For example: $$a+b-c=\sqrt{2}$$ or $$a+b-c=0.3$$.

Guess statement (1) is saying: "a, b and c are consecutive integers". The word "consecutive" is redundant here. Just knowing that "a, b and c are integers" is enough to say that this statement is sufficient to answer the question. And the answer would be NO: a, b and c are integers --> $$a+b-c=integer$$ --> $$2(a+b-c)=even$$.

Statement (2) is clearly not sufficient.

What numbers can be substituted for A, B, and C and when multiplied by 2 gives you an odd integer?

Note that stem does not say that a, b and c are integers.

So for example: a=3/2, b=0, c=0 --> $$2(a+b-c)=3$$. As I said if $$a+b-c=\frac{odd}{2}$$, then $$2(a+b-c)=2*\frac{odd}{2}=odd$$. This option is ruled out by statement (1), which says that a, b and c are integers.

Hope it's clear.
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Re: GmatClub Test: Number Properies - I (DS) [#permalink]

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07 May 2010, 22:13
Thanks Bunuel.

I think I need some revision also on Number Properties.
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Re: GmatClub Test: Number Properies - I (DS) [#permalink]

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08 May 2010, 04:56
Bunuel wrote:
ykaiim wrote:
Is 2(a+b-c) an odd integer?

1. a, b and c are consecutive numbers
2. b=a+c

The OA is A. But, I think it is incorrect.
Case1: 0,1,2 the a+b-c = -1 (Yes)
Case2: 1,2,3 the a+b-c = 0 (No)

Can someone tell me where I am wrong?

$$2(a+b-c)$$ can be:
odd, in case $$a+b-c=\frac{odd}{2}$$;
even, in case $$a+b-c=integer$$
not an integer at all, in case $$a+b-c$$ does not equal to any above. For example: $$a+b-c=\sqrt{2}$$ or $$a+b-c=0.3$$.

Guess statement (1) is saying: "a, b and c are consecutive integers". The word "consecutive" is redundant here. Just knowing that "a, b and c are integers" is enough to say that this statement is sufficient to answer the question. And the answer would be NO: a, b and c are integers --> $$a+b-c=integer$$ --> $$2(a+b-c)=even$$.

Statement (2) is clearly not sufficient.

totally right
I assumed that a, b and c were integers

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Re: GmatClub Test: Number Properies - I (DS) [#permalink]

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16 May 2010, 15:22
yup A must be the ans

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Re: Is 2(a+b-c) an odd integer? 1. a, b and c are consecutive [#permalink]

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08 Nov 2013, 12:38
If we substitute b = a + c in 2(a+b-c), we get 4a. Now, whatever the value of a, the outcome will always be even. This statement should be sufficient too. In my opinion, the answer should be D.

I am not sure that whether what I have done is correct but, this is what came to my mind when I was attempting this question; I marked D.
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Re: Is 2(a+b-c) an odd integer? 1. a, b and c are consecutive [#permalink]

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09 Nov 2013, 02:47
AasaanHai wrote:
If we substitute b = a + c in 2(a+b-c), we get 4a. Now, whatever the value of a, the outcome will always be even. This statement should be sufficient too. In my opinion, the answer should be D.

I am not sure that whether what I have done is correct but, this is what came to my mind when I was attempting this question; I marked D.

is-2-a-b-c-an-odd-integer-1-a-b-and-c-are-consecutive-93832.html#p722067
is-2-a-b-c-an-odd-integer-1-a-b-and-c-are-consecutive-93832.html#p722073

The correct answer is A, not D.
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Re: Is 2(a+b-c) an odd integer? 1. a, b and c are consecutive [#permalink]

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13 May 2016, 01:25
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Is 2(a+b-c) an odd integer? 1. a, b and c are consecutive [#permalink]

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26 May 2016, 07:52
Bunuel wrote:
AasaanHai wrote:
If we substitute b = a + c in 2(a+b-c), we get 4a. Now, whatever the value of a, the outcome will always be even. This statement should be sufficient too. In my opinion, the answer should be D.

I am not sure that whether what I have done is correct but, this is what came to my mind when I was attempting this question; I marked D.

is-2-a-b-c-an-odd-integer-1-a-b-and-c-are-consecutive-93832.html#p722067
is-2-a-b-c-an-odd-integer-1-a-b-and-c-are-consecutive-93832.html#p722073

The correct answer is A, not D.

@Bunuel- Shouldn't the OA for this question be E?
You have proved that neither statement 1 nor 2 is sufficient.

Also, I request the author to update the OA for this question.

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Re: Is 2(a+b-c) an odd integer? 1. a, b and c are consecutive [#permalink]

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26 May 2016, 08:59
kanav06 wrote:
Bunuel wrote:
AasaanHai wrote:
If we substitute b = a + c in 2(a+b-c), we get 4a. Now, whatever the value of a, the outcome will always be even. This statement should be sufficient too. In my opinion, the answer should be D.

I am not sure that whether what I have done is correct but, this is what came to my mind when I was attempting this question; I marked D.

is-2-a-b-c-an-odd-integer-1-a-b-and-c-are-consecutive-93832.html#p722067
is-2-a-b-c-an-odd-integer-1-a-b-and-c-are-consecutive-93832.html#p722073

The correct answer is A, not D.

@Bunuel- Shouldn't the OA for this question be E?
You have proved that neither statement 1 nor 2 is sufficient.

Also, I request the author to update the OA for this question.

This is a poor quality/reworded question. Ignore it and move on.
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Re: Is 2(a+b-c) an odd integer? 1. a, b and c are consecutive   [#permalink] 26 May 2016, 08:59
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